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hoa [83]
3 years ago
9

Derive the equation of the parabola with a focus at (0, 1) and a directrix of y = −1. f(x) = −one fourth x^2

Mathematics
1 answer:
LuckyWell [14K]3 years ago
4 0
Your answer :<span>f(x) = one fourth x^2 </span>
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H v is help me!!!!!!!!
Anon25 [30]

Answer:

He spent $15.51

Step-by-step explanation:

0.55x28.2=15.51

Hope this helps

^_^

8 0
2 years ago
Multiples of 6 are also multiples of 3
Black_prince [1.1K]

Answer:

(☞゚ヮ゚)☞

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
What is the domain of the radical function shown on the graph? GRAPH IS IN THE PIC BELOW. A.
irina1246 [14]

Given:

The graph of a radical function.

To find:

The domain of the given radical function.

Solution:

We know that, domain is the set of input values or we can say domain is the set of x-values for which the function is defined.

From the given graph it is clear that, for each value of x there is a y-value. It means the function is defined for all real values of x. So,

Domain = Set of all real numbers.

Therefore, the correct option is A.

8 0
2 years ago
Show whether or not y=x+3 is tangential to the curve y^2=x​
wolverine [178]

The line y = x + 3 has slope 1, so we look for points on the curve where the tangent line, whose slope is dy/dx, is equal to 1.

y² = x

Take the derivative of both sides with respect to x, assuming y = y(x) :

2y dy/dx = 1

dy/dx = 1/(2y)

Solve for y when dy/dx = 1 :

1 = 1/(2y)

2y = 1

y = 1/2

When y = 1/2, we have x = y² = (1/2)² = 1/4. However, for the given line, when y = 1/2, we have x = y - 3 = 1/2 - 3 = -5/2.

This means the line y = x + 3 is not a tangent to the curve y² = x. In fact, the line never even touches y² = x :

x = y²   ⇒   y = y² + 3   ⇒   y² - y + 3 = 0

has no real solution for y.

3 0
2 years ago
In 2011, a U.S. Census report determined that 71% of college students work. A researcher thinks this percentage has changed sinc
coldgirl [10]

Answer:

Note: The full question is attached as picture below

a) Hо : p = 0.71

Ha : p ≠ 0.71

<em>p </em>= x / n

<em>p </em>= 91/110

<em>p </em>= 0.83.

1 - Pо = 1 - 0.71 = 0.29.

b) Test statistic = z

= <em>p </em>- Pо / [√Pо * (1 - Pо ) / n]

= 0.83 - 0.71 / [√(0.71 * 0.29) / 110]

= 0.12 / 0.043265

= 2.77360453

Test statistic = 2.77

c) P-value

P(z > 2.77) = 2 * [1 - P(z < 2.77)] = 2 * 0.0028

P-value = 0.0056

∝ = 0.01

P-value < ∝

Reject the null hypothesis.  There is sufficient evidence to support the researchers claim at the 1% significance level.

6 0
3 years ago
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