Answer:
After 25 years the population will be:
- Australia: 22271200
- China: 1580220878
- Mexico: 157380127
- Zaire: 112794819
Step-by-step explanation:
Growth rate problem that has a growth rate proportional to the population size can be solved using the equation:
P(t) = P₀eʳᵗ
- t is your unit of time. It could be days, or hours, or minutes. It changes depending on each problem. In this problem, t is measured in years because you're jumping from 2000 to 2025. Years just makes the most sense to measure that leap in time.
- P(t) is the population at time t. An example in this problem could be P(20) would be the population 20 years after the initial count. or maybe P(12) would be the population 12 years after the initial count. or P(0) would be the initial count of the population.
- P₀ is the initial population at P(0)
- r is the growth rate.<u><em> Don't forget to convert the percentage to its decimal form</em></u>
Now that everything is set out, lets use the equation to solve for our answer.
P(t) = P₀eʳᵗ
<u>Australia:</u>

after 25 years

<u>China:</u>

after 25 years:

<u>Mexico:</u>

after 25 years:

<u>Zaire:</u>

after 25 years:

Answer:
the answer might be 0.86 I don't know though
proportional relationship in our everyday life: When we put gas in our car, there is a relationship between the number of gallons of fuel that we put in the tank and the amount of money we will have to pay. In other words, the more gas we put in, the more money we'll pay.
<span>Let r(x,y) = (x, y, 9 - x^2 - y^2)
So, dr/dx x dr/dy = (2x, 2y, 1)
So, integral(S) F * dS
= integral(x in [0,1], y in [0,1]) (xy, y(9 - x^2 - y^2), x(9 - x^2 - y^2)) * (2x, 2y, 1) dy dx
= integral(x in [0,1], y in [0,1]) (2x^2y + 18y^2 - 2x^2y^2 - 2y^4 + 9x - x^3 - xy^2) dy dx
= integral(x in [0,1]) (x^2 + 6 - 2x^2/3 - 2/5 + 9x - x^3 - x/3) dx
= integral(x in [0,1]) (28/5 + x^2/3 + 26x/3 - x^3) dx
= 28/5 + 40/9 - 1/4
= 1763/180 </span>