Answer:
Mrs. Habib will have 22.25 feet of border left after she puts border around the board.
Step-by-step explanation:
You must find the perimeter of the board and subtract it from the amount of border she has to find how much she will have left after she uses it. The formula for perimeter is
, where
the length of the board, and
the width of the board. You will add those together and multiply them by 2 because there are 4 sides to a rectangle. That means this equation will look like:

Now you can just solve for the perimeter.


The perimeter is 24 feet. That means it will take 24 feet of border to cover her board. In order to find out how much she'll have left over, just subtract 24 from the total amount of border she has.
Therefore Mrs. Habib will have 22.25 feet of border left over after she covers the bulletin board.
Answer:
10
Step-by-step explanation:
To find the area of a parallelogram you need to use the expression A = bh
When you plug that in it will be 120 = 12b
After this, you need to solve (10)
Answer:
Decreased by 20%.
16 lbs is 80% of 20 lbs.
Step-by-step explanation:

y × 20 = 16 × 100
20y = 1600
20y ÷ 20 = 1600 ÷ 20
y = 80
100% - 80% = 20%
Since she has painted 60% of her bedroom so far, 40% must remain. In order to know how many square feet that is, we take the total amount of square feet she needs to paint and multiply it by 0.4
45*0.4 = 18 square feet
Split up the interval [2, 5] into

equally spaced subintervals, then consider the value of

at the right endpoint of each subinterval.
The length of the interval is

, so the length of each subinterval would be

. This means the first rectangle's height would be taken to be

when

, so that the height is

, and its base would have length

. So the area under

over the first subinterval is

.
Continuing in this fashion, the area under

over the

th subinterval is approximated by

, and so the Riemann approximation to the definite integral is

and its value is given exactly by taking

. So the answer is D (and the value of the integral is exactly 39).