X: 1, 2
J: 1, 5
Y: -3, 5
Start with the x-axis which is the horizontal line, and then the y-axis which is the vertical line, then you just find the dot and the points!
Im sorry Im not that good at geometry.
<u>⇨ By prime factorization method:</u>
![\begin{array}{r | l}{\sf{2 & {\sf14,28,31} \\\cline{2-2} {\sf2 & {\sf7,14,31 \\\cline{2-2} {\sf7 & {\sf7,7,31 \\\cline{2-2} {\sf31 & {\sf1,1,31 \\\cline{2-2} & {\sf1,1,1\end{array}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Br%20%7C%20l%7D%7B%5Csf%7B2%20%26%20%7B%5Csf14%2C28%2C31%7D%20%5C%5C%5Ccline%7B2-2%7D%20%7B%5Csf2%20%26%20%7B%5Csf7%2C14%2C31%20%5C%5C%5Ccline%7B2-2%7D%20%7B%5Csf7%20%26%20%7B%5Csf7%2C7%2C31%20%5C%5C%5Ccline%7B2-2%7D%20%7B%5Csf31%20%26%20%7B%5Csf1%2C1%2C31%20%5C%5C%5Ccline%7B2-2%7D%20%26%20%7B%5Csf1%2C1%2C1%5Cend%7Barray%7D)
![{\sf{LCM\: = \:2 \:x\: 2 \:x\: 7 \:x\: 31}}\\\\{\sf{LCM \:= \:868}}\\}\\{\sf{Therefore,}}\\\\{\sf{LCM\:(14,\: 28,\: 31)\: = \:868](https://tex.z-dn.net/?f=%7B%5Csf%7BLCM%5C%3A%20%3D%20%5C%3A2%20%5C%3Ax%5C%3A%202%20%5C%3Ax%5C%3A%207%20%5C%3Ax%5C%3A%2031%7D%7D%5C%5C%5C%5C%7B%5Csf%7BLCM%20%5C%3A%3D%20%5C%3A868%7D%7D%5C%5C%7D%5C%5C%7B%5Csf%7BTherefore%2C%7D%7D%5C%5C%5C%5C%7B%5Csf%7BLCM%5C%3A%2814%2C%5C%3A%2028%2C%5C%3A%2031%29%5C%3A%20%3D%20%5C%3A868)
![{\boxed{\sf{LCM\:=\:868}}](https://tex.z-dn.net/?f=%7B%5Cboxed%7B%5Csf%7BLCM%5C%3A%3D%5C%3A868%7D%7D)
Answer:
.
Step-by-step explanation: