Choose a tool or a device you can investigate. It must not have any source of power other than the person using it. It must use
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Answer:
The magnitude of the gravitational field strength near Earth's surface is represented by approximately .
Explanation:
Let be M and m the masses of the planet and a person standing on the surface of the planet, so that M >> m. The attraction force between the planet and the person is represented by the Newton's Law of Gravitation:
Where:
- Mass of the planet Earth, measured in kilograms.
- Mass of the person, measured in kilograms.
- Radius of the Earth, measured in meters.
- Gravitational constant, measured in
.
But also, the magnitude of the gravitational field is given by the definition of weight, that is:
Where:
- Mass of the person, measured in kilograms.
- Gravity constant, measured in meters per square second.
After comparing this expression with the first one, the following equivalence is found:
Given that ,
and
, the magnitude of the gravitational field near Earth's surface is:
The magnitude of the gravitational field strength near Earth's surface is represented by approximately .
Answer:
<u>Work done by the force acting on a body is defined as the product of force and displacement of the body in the direction of the force.</u><u> </u> It is a scalar quantity. Force acting on the body must produce a displacement for the work is to be done by the force. Thus, for the work to be done, the following conditions must be fulfilled:
A force must be applied and the applied force must produce a displacement in any direction except perpendicular to the direction of the force.
Mathematically,
( in the direction of force)
i.e W= F•D
The SI unit of force is Newton (N) and that of displacement of a metre (M). So the unit of work is Newton metre(Nm) which is joule (J).
Thus, one joule work is said to be done when one Newton force displaces a body through one metre in its own direction.
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