Answer: No. Circuit should be closed.
Explanation:
A changing magnetic field induces emf in a circuit which is placed in it. This induced emf causes current to flow through it. This is given by Faraday's law which states that induced emf results due to rate of change of magnetic flux.
Current flows only through a closed circuit. Thus, when a wire is moved up and down in a magnetic field, it will not induce emf because the wire does not form a loop. It is an open circuit.
P=4800kgm/s
As
p=mΔv
where p is momentum, m is mass and v is velocity
Given values is
m =1200kg
Δv= 17m/s-13m/s=4m/s
Now
p=mΔv
p=(1200kg)*(4m/s)
p=4800kgm/s
Well it’s a prediction so u can’t be wrong but I would say there would be way more powerful than what it was
Answer:
0.025 m
0.059166 m
Explanation:
P = Pressure
A = Area
x = Compression of spring
Force is given by
From Hooke's law
The spring is compressed 0.025 m
In the second case
Net force would be
Compression would be
The compression of the spring is 0.059166 m
Answer:
F_f = 25 N
Explanation:
Given:
- Force applied by Albert F = 49 N
- Mass of the box m = 12 kg
- Acceleration of the box a = 2 m /s^2
- Frictional Force = F_f
Find:
what is the magnitude of the frictional force pushing backward on the box
Solution:
- Apply newton's second Law of motion on the box. With the applied force and the frictional are the only horizontal forces. Applied force in the direction of acceleration and Frictional Force F_f opposite in direction of the motion. Then we have from the Equation of motion:
F_net = m*a
F_net = F - F_f
F - F_f = m*a
- Plug in the values:
F_f = F - m*a
F_f = 49 - 12*2
F_f = 25 N