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Ad libitum [116K]
3 years ago
7

A large farm has 75 acres of wheat and 62.5 acres of corn. The farm crew can harvest the the wheat from 12 acres and the corn fr

om 10 acres per day. In how many days will all of the fields be harvested?
Mathematics
1 answer:
Leviafan [203]3 years ago
4 0
In a Farm, there are:
=> 75 acres of wheat
=> 62.5 acres of corn
In each day, the farm crew can harvest:
=> 12 acres of wheat
=> 10 acres of corn
Find how many days can the farm crew harvest all of the plants,
=> 75 / 12
=> 6.25, thus the farm crew will take 6.25 days to be able to harvest acres of wheat
=> 62.5 / 10
=> 6.25, thus the farm crew will take 6.25 days also to harvest acres of corn.



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Sarah used properties of operations to write the following three equivalent expressions to .
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BRAINLIEST ANSWER WINS! A satellite is to be put into an elliptical orbit around a moon as shown below. A vertical ellipse is sh
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Answer:

D. x²/1953²  + y²/ 1466² = 1

Step-by-step explanation:

==>Given:

Radius of spherical moon = 1000km

Distance of satellite from moon surface = 953km to 466km

==>Required:

Derived equation of ellipse

==>Solution:

The formula for driving an equation of ellipse is given as:

x²/a² + y²/b² = 1

Where,

a = length of the semi-major axis, while,

b = length of the semi-major axis

Since we are told that the satellite distance to the surface of the moon varies from 953km to 466km, values of a and b is calculated by summing each length to the radius of the moon as follows:

a = radius of moon + the larger distance of the satellite = 1000+953 = 1,953km

b = radius of moon + the smaller distance of the satellite = 1000+466 = 1,466km

Thus, the equation of the ellipse would be:

x²/1953²  + y²/ 1466² = 1

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2 years ago
What is the value of x?<br> X+4/9=3/4
Mashcka [7]

Answer:

11/36

Step-by-step explanation:

Here are the steps:

Step 1: Find a common denominator for both of the fractions

4/9 --> 27/36 (Multiply top and bottom by 4)

3/4 --> 16/36 (Multiply top and bottom by 9)

This is the smallest common denominator

Step 2: Subtract:

27/36 - 16/36 = 11/36

Soo...

x = 11/36

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2 years ago
Calculate area and perimeter​
mina [271]

Answer:

area ≈ 12.505

perimeter ≈  16.1684

Step-by-step explanation:

We are given

- the radius of the circle (and therefore area of the circle)

- the area of the triangle

We want to find

- angle AOB/AOT. We want to find this because 360/the angle gives us how many OABs fit into the circle. For example, if AOT was 30 degrees, 360/30 = 12 (there are 360 degrees in a circle, so that's where 360 comes from). The area of the circle is equal to πr² = π6² = 36π, and because AOT is 30 degrees, there are 12 equal parts of sector OAB in the circle, so 36π/12=3π would be the area of the sector. A similar conclusion can be reached from the circumference instead of the area to find the distance between A and B along the circle, and OA + AB + BO = the perimeter of the minor sector.

First, we can say that OAT is a right triangle because a tangent line is perpendicular to the line from the center to the point on the circle, so AT is perpendicular to OA. This forms two right angles, one of which is OAT

One thing that we can start to solve is AT. We know that the area of a triangle is equal to base * height /2, and the height of this triangle is AO, with the base being AT. Therefore, we can say

15 = AO * AT / 2

15 = 6 * AT / 2

15 = 3 * AT

divide both sides by 3 to isolate AT

AT = 5

Because OAT is a right triangle, we can say that the hypotenuse ² =  the sum of the squares of the two other lengths. The hypotenuse is opposite of the largest angle (in this case, the right angle, as in a right triangle, the right angle is always the largest), so it is OT in this case. The other two sides are OA and AT, so we can say that

OA² + AT² = OT²

5²+6² = OT²

25+36=61=OT²

square root both sides

OT = √61

Next, the Law of Sines states that

sinA/a = sinB/b = sinC/c with angles A, B, and C with sides a, b, and c. Corresponding sides are opposite their corresponding angles, so in this case, AT corresponds to angle AOT, OT corresponds to angle OAT, and AO corresponds to angle ATO.

We want to find angle AOT, as stated earlier, so we have

sin(OAT)/OT = sin(ATO)/OA = sin(AOT)/AT

We know the side lengths as well as OAT/sin(OAT) and want to figure out AOT/sin(AOT), so one equation that helps us get there is

sin(OAT)/OT = sin(AOT)/AT, encompassing our 3 known values and isolating the one unknown. We thus have

sin(90)/√61 = sin(AOT) /5

plug in sin(90) = 1

1/√61 = sin(AOT)/5

multiply both sides by 5 to isolate sin(AOT)

5/√61 = sin(AOT)

we can thus say that

arcsin(5/√61) = AOT ≈39.80557

As stated previously, given ∠AOT, we can find the area and perimeter of the sector. There are 360/39.80557 ≈ 9.04396 equal parts of sector OAB in the circle. The area of the circle is πr² = 36π, so 36π / 9.04396 ≈ 12.505 as the area. The circumference is equal to π * diameter = π * 2 * radius = 12 * π, and there are 9.04396 equal parts of arc AB in the circumference, so the length of arc is 12π / 9.04396 ≈ 4.1684. Add that to OA and OB (both are equal to the radius of 6, as any point from the center to a point on the circle is equal to the radius) to get 6+6 + 4.1684 = 16.1684 as the perimeter of the sector

5 0
3 years ago
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