To solve this problem, we should recall that
the change in enthalpy is calculated by subtracting the total enthalpy of the reactants
from the total enthalpy of the products:
ΔH = Total H of products – Total H of reactants
You did not insert the table in this problem, therefore I
will find other sources to find for the enthalpies of each compound.
ΔHf CO2 (g) = -393.5 kJ/mol
ΔHf CO (g) = -110.5 kJ/mol
ΔHf Fe2O3 (s) = -822.1 kJ/mol
ΔHf Fe(s) = 0.0 kJ/mol
Since the given enthalpies are still in kJ/mol, we have to
multiply that with the number of moles in the formula. Therefore solving for ΔH:
ΔH = [<span>3 mol </span><span>( − </span><span>393.5 </span>kJ/mol<span>) + 1 mol (</span>0.0
kJ/mol)<span>] − [</span><span>3 mol </span><span>( − </span><span>110.5 </span>kJ/mol<span>) + </span><span>2 mol </span><span>( − </span><span>822.1 </span>kJ/mol<span>)]</span>
ΔH = <span>795.2
kJ</span>
The amount of energy required to remove an electron from an atom. 2 ionization energy
A bond where electrons are shared unequally, resulting in a positively charged end and a negatively charged end of the molecule, 4 polar covalent bond
The tendency of an atom to attract a pair of electrons and bond with another atom; increases from bottom-left toward top-right of the periodic table. 3. Electronegativity
A bond where electrons are shared equally, or polar bonds in the molecule cancel each other out. 5. Non polar covalent bond
Shell or energy level where electrons are found. 1. Orbital
<span>A substance has a melting point of 0°c and a boiling point of 100°c the substance is most likely:
</span>A) water
Answer:The change in concentration of a reactant or product per unit time
Explanation:
Answer:
6.09 M
Explanation:
M(HCl) = 1 +35.5 = 36.5 g/mol
85.6 g * 1 mol/36.5 g = 2.3452 mol HCl
Molarity = mol solute/ L solution = 2.3452 mol/0.385 L = 6.09 mol/L =6.09 M