<span>1. capable of being dissolved in a liquid= Soluble
</span><span>
2. not capable of being dissolved in a liquid= Insoluble
</span><span>3. to break up in unit parts to form a solution= Dissolve
</span>
<span>4. the substance that is dissolved in the solution= Solute
</span>
<span>5. the substance that does the dissolving= Solvent
please be more clear in the way you word you questions from now on. I had a hard time understanding what you meant. I hope this helps.
</span>
Given:
F_gravity = 10 N
F_tension = 25 N
Let's find the net centripetal force exterted on the ball.
Apply the formula:
From the given figure, the force acting towards the circular path will be positive, while the force which points directly away from the center is negative.
Hence, the tensional force is positive while the gravitational force is negative.
Thus, we have:
Therefore, the net centripetal force exterted on the ball is 15 N.
ANSWER:
15 N
Explanation:
Formula for calculating the area of a rectangle A = Length *width
For statement A;
Given area of a rectangle with measured length = 2.536 mm and width = 1.4 mm.
Area of the rectangle = 2.536mm * 1.4mm
Area of the rectangle = 3.5504mm²
The rule of significant figures states that we should always convert the answer to the least number of significant figure amount the given value in question. Since 1.4mm has 2 significant figure, hence we will convert our answer to 2 significant figure.
Area of the rectangle = 3.6mm² (to 2sf)
For statement B;
Given area of a rectangle with measured length = 2.536 mm and width = 1.41 mm.
Area of the rectangle = 2.536mm * 1.41mm
Area of the rectangle = 3.57576mm²
Similarly, Since 1.41mm has 3 significant figure compare to 2.536 that has 4sf, hence we will convert our answer to 3 significant figure.
Area of the rectangle = 3.58mm² (to 3sf)
Based on the conversion, it can be seen that 3.6mm² is greater than 3.58mm², hence the area of rectangle in statement A is greater than the area of the rectangle in statement B.
Answer:
Option C is the correct answer.
Explanation:
We have ideal gas equation, PV = nRT
Volume of tank, V = 1 m³
Mass of water = 10 kg
Mass of 1 mole of water = 18 g = 0.018 kg
Number of moles,
Temperature, T = 160 °C = 160 + 273 = 433 K
Ideal gas constant, R = 8.314 JK⁻¹mol⁻¹
Substituting
P x 1 = 555 x 8.314 x 433
P = 2000000 Pa = 2000 kPa
The pressure in the tank is 2000 kPa
Option C is the correct answer.
Answer : to pick up safely..
Place one hand under her front legs and position your other hand so that it supports her back legs and hind quarters.