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Sphinxa [80]
3 years ago
8

What is the frequency of an electromagnetic wave with a wavelength of 20cm ?

Physics
1 answer:
zhannawk [14.2K]3 years ago
3 0

Wavelength  = 20 m = 0.20 m

frequency = 3*10^8 / 0.20 = 1.5 * 10^9 Hertz


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When you see a quantity like 20 m/s N, how do you know that it's a vector quantity and not a scalar quantity?
KengaRu [80]

We know that 20 m/s N is a vector quantity because N in the expression signifies the direction

<h3>What is a vector quantity?</h3>

This is a which have both magnitude and direction. Example include:

  • Velocity
  • Displacement
  • Force
  • Acceleration
  • Moment
  • Weight

<h3>How to determine whether 20 m/s N is a vector quantity</h3>
  • 20 m/s indicates just the speed i.e magnitude
  • 20 m/s N indicates the speed i.e magnitude why the N indicates the direction.

Thus, we can conclude that 20 m/s N is a vector quantity because it has both magnitude and direction.

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5 0
2 years ago
The Pasig Revolving Tower has an estimated height of 45.23 meters. How high is it in yard? ​
hichkok12 [17]

Answer:

50.26

I hope its help

Thank you

6 0
3 years ago
A 4 kg textbook sits on a desk. It is pushed horizontally with a 50 N applied force against a 15 N frictional force.
GarryVolchara [31]

a) See free-body diagram in attachment

b) The book is stationary in the vertical direction

c) The net horizontal force is 35 N in the forward direction

d) The net force on the book is 35 N in the forward horizontal direction

e) The acceleration is 8.75 m/s^2 in the forward direction

Explanation:

a)

The free-body diagram of a body represents all the forces acting on the body using arrows, where the length of each arrow is proportional to the magnitude of the force and points in the same direction.

From the diagram of this book, we see there are 4 forces acting on the book:

- The applied force, F = 50 N, pushing forward in the horizontal direction

- The frictional force, F_f = 15 N, pulling backward in the horizontal direction (the frictional force always acts in the direction opposite to the motion)

- The weight of the book, W=mg, where m is the mass of the book and g=9.8 m/s^2 is the acceleration of gravity, acting downward. We can calculate its magnitude using the mass of the book, m = 4 kg:

W=(4)(9.8)=39.2 N

- The normal reaction exerted by the desk on the book, N, acting upward, and balancing the weight of the book

b)

The book is in equilibrium in the vertical direction, therefore there is no motion.

In fact, the magnitude of the normal reaction (N) exerted by the desk on the book is exactly equal to the weight of the book (W), so the equation of motion along the vertical direction is

N-W=ma

where a is the acceleration; however, since N = W, this becomes

a=0

And since the book is initially at rest on the desk, this means that there is no motion.

c)

We said there are two forces acting in the horizontal direction:

- The applied force, F = 50 N, forward

- The frictional force, F_f = 15 N, backward

Since they act along the same line, we can calculate their resultant as

\sum F = F - F_f = 50 - 15 = 35 N

and therefore the net force is 35 N in the forward direction.

d)

The net force is obtained as the resultant  of the net forces in the horizontal and vertical direction. However, we have:

- The net force in the horizontal direction is 35 N

- The net force in the vertical direction is zero, because the weight is balanced by the normal reaction

Therefore, this means that the total net force acting on the book is just the net force acting on the horizontal direction, so 35 N forward.

e)

The acceleration of the book can be calculated by using Newton's second law:

\sum F = ma

where

\sum F is the net force

m is the mass

a is the acceleration

Here we have:

\sum F = 35 N (in the forward direction)

m = 4 kg

Therefore, the acceleration is

a=\frac{\sum F}{m}=\frac{35}{4}=8.75 m/s^2 (forward)

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8 0
4 years ago
____________________ (is/are) one type of tectonic event captured in geologic maps.
dangina [55]

Answer:

Seismic activityis/are) one type of tectonic event captured in geologic maps.

3 0
2 years ago
Calculate the density of a rod of metal in g/cm3, with a mass of 9.58g, a diameter of 8 mm and a height of 3.5cm
Ganezh [65]

Answer:

5.448 g/cm³

Explanation:

Density: This is defined as the ratio of the mass of a body to its volume.

The unit of density is kg/m³ other sub units are g/cm³, mg/mm³.

From the question,

D = m/πr²h......................... Equation 1

Where D = density, m = mass, r = radius, h = height.

Given: m = 9.58 g, r = 8/2 mm = 4 mm = 0.4 cm, h = 3.5 cm

Substitute this values into equation 1

D = 9.58/(3.14×0.4²×3.5)

D = 5.448 g/cm³

Hence the density of the metal rod is 5.448 g/cm³

8 0
3 years ago
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