Answer and Explanation:
Let:
The equation representing a simple harmonic motion, where:
As you may know the derivative of the position is the velocity and the derivative of the velocity is the acceleration. So we can get the velocity and the acceleration by deriving the position:
Also, you may know these fundamental formulas:
Now, using the previous information and the data provided by the problem, let's solve the questions:
(a)
(b)
(c)
(d)
We can extract the phase of the motion, the angular frequency and the amplitude from the equation provided by the problem:
(e)
(f)
- The wavelength of the red light in "nanometer" is 7×
- Wavelength is given as : 7×
meter
- 1 nanometer = (
meter)
- Let X= value of the wavelength in nanometer.
1 nanometer = meter
X nanometer = 7× meter
- <em>If we Cross multiply</em>
X nanometer = (
)
X= 7× nanometer
Therefore, the wavelength in "nanometer" is 7×
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1 is 0n I believe 2 8n or 2n 3 would be 10n 4 is 0n or 12n
Answer:
1.08 s
Explanation:
From the question given above, the following data were obtained:
Height (h) reached = 1.45 m
Time of flight (T) =?
Next, we shall determine the time taken for the kangaroo to return from the height of 1.45 m. This can be obtained as follow:
Height (h) = 1.45 m
Acceleration due to gravity (g) = 9.8 m/s²
Time (t) =?
h = ½gt²
1.45 = ½ × 9.8 × t²
1.45 = 4.9 × t²
Divide both side by 4.9
t² = 1.45/4.9
Take the square root of both side
t = √(1.45/4.9)
t = 0.54 s
Note: the time taken to fall from the height(1.45m) is the same as the time taken for the kangaroo to get to the height(1.45 m).
Finally, we shall determine the total time spent by the kangaroo before returning to the earth. This can be obtained as follow:
Time (t) taken to reach the height = 0.54 s
Time of flight (T) =?
T = 2t
T = 2 × 0.54
T = 1.08 s
Therefore, it will take the kangaroo 1.08 s to return to the earth.
Liquids do not have a definite size and always take the shape of the container they're in.
