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seraphim [82]
3 years ago
8

Simplify the trigonometric expression. 1/1+sin 0+1/1-sin 0

Mathematics
1 answer:
Trava [24]3 years ago
3 0
Assuming you mean (1/1+sin 0)+(1/1-sin 0), then we have to first remember that the sin of 0 is 0. The expression would now be (1/1+0)+(1/1-0), which is also just (1/1)+(1/1) or 1+1. This comes out to 2, so the expression can be evaluated as 2.
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Ling worked three more hours on Tuesday than she did on Monday. On Wednesday, she worked one hour more than twice the number of
Nina [5.8K]

Let x be the number of hours ling work on monday.

We know that she worked three more hours on tuesday that in monday, this can be express as :

 x+3

We also know that in wednesday she worked on more hour than twice the number on mondays, this can be expressed as:

2x+1

The total number of hours she worked this three days in two more than five the number of hours she worked on monday, this can be express as :

5x+2\\

Now , once we have all the expressions we add the expressions of the days and equate them to the total

x+(x+3)+(2x+1)=5x+2

Now we solve the equation

x+(x+3)+(2x+1)=5x+2\\x+x+3+2x+1=5x+2\\4x+4=5x+2\\5x-4x=4-2\\x=2

Therefore , she worked 2 hours on monday.

PLEASE MARK ME AS BRAINLIEST

7 0
3 years ago
Read 2 more answers
I don't understand how to do this. Can someone help?
miskamm [114]
Time used for the call to Zurich: ($5-$1.25)/$0.25=15 minutes
15minutes+3minutes=18minutes
Time used for the call to London: ($7.25-$1.25)/$0.25=24 minutes
24minutes+3minutes=27minutes
Difference between the two calls:27-18=9minutes
3 0
3 years ago
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