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Serhud [2]
3 years ago
14

WILL MARK BRAINLIEST

Mathematics
1 answer:
Klio2033 [76]3 years ago
7 0

The answer is 6.30 seconds, you can find this by graphing the equation. you can use desmos for help graphing digitally if you have to.

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To write the problem out as an equation, let 'n' equal your number. 

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0.9898 = 98.98% probability that there will not be more than one failure during a particular week.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given interval.

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Calculate the probability that there will not be more than one failure during a particular week.

Probability of at most one failure, so:

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Then

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-0.15}*0.15^{0}}{(0)!} = 0.8607

P(X = 1) = \frac{e^{-0.15}*0.15^{1}}{(1)!} = 0.1291

Then

P(X \leq 1) = P(X = 0) + P(X = 1) = 0.8607 + 0.1291 = 0.9898

0.9898 = 98.98% probability that there will not be more than one failure during a particular week.

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