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3 years ago

WILL MARK BRAINLIEST

1 answer:

Klio2033 [76]3 years ago

7 0

The answer is 6.30 seconds, you can find this by graphing the equation. you can use desmos for help graphing digitally if you have to.

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The price of heating oil rose from $1.10 per gallon to $1.43 per gallon. What is the percent of

ZanzabumX [31]

Answer:

30% increase

Step-by-step explanation:

1.43 - 1.10 = 0.33

0.33 = 30% of 1.10

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3 years ago

Three times a number subtracted from the product of fifteen and the reciprocal of a number

ASHA 777 [7]

To write the problem out as an equation, let 'n' equal your number.

(15 x 1/n) - 3n

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4 years ago

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Step-by-step explanation:

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If electricity power failures occur according to a Poisson distribution with an average of 3 failures every twenty weeks, calcul

Wittaler [7]

Answer:

0.9898 = 98.98% probability that there will not be more than one failure during a particular week.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

3 failures every twenty weeks

This means that for 1 week, $\mu = \frac{3}{20} = 0.15$

Calculate the probability that there will not be more than one failure during a particular week.

Probability of at most one failure, so:

$P(X \leq 1) = P(X = 0) + P(X = 1)$

Then

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-0.15}*0.15^{0}}{(0)!} = 0.8607$

$P(X = 1) = \frac{e^{-0.15}*0.15^{1}}{(1)!} = 0.1291$

Then

$P(X \leq 1) = P(X = 0) + P(X = 1) = 0.8607 + 0.1291 = 0.9898$

0.9898 = 98.98% probability that there will not be more than one failure during a particular week.

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3 years ago

Plzzzzzzz helpppp right answer gets brainly

Citrus2011 [14]

Answer:

Algebra I believe

Step-by-step explanation:

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4 years ago

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