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4 years ago

8 which of the following numbers Is Irrational?

Mathematics

1 answer:

snow_tiger [21]4 years ago

4 0

It’s the square root of 2 (100%)

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Word Problem

tensa zangetsu [6.8K]

Jeanette is not correct. In an arithmetic sequence, to find the next number, you have to add the common difference. If the first number is -27, to find the next number you have to add 5, making the next number -22. The pattern of adding 5 would continue making the first 5 terms of the sequence : -27,-22,-17,-12,- 7.

7 0

3 years ago

SOMEONE HELP!!!!!! Don’t use what websites! And please like list answer 1,2,3, and 4

harkovskaia [24]

Answer:

1. 24 2. 20 3. 1.75(I think) 4. 11

Step-by-step explanation:

3 might be incorrect but The others seem more correct than ever :)

8 0

3 years ago

Jocelyn solved the following division problem: Mr. Martin brings two gallons of

denis-greek [22]

Answer:

she would probably have have 101.4 oz which is about 6 bottles left over this is of course if those bottles can hold 16.9 oz which is the average water bottle intake(<u><em>you forgot that info</em></u>) maybe put more information for the next problem you decide to ask.

Step-by-step explanation:

your welcome

7 0

3 years ago

Given f(x)=2x^2+3x-5 for what values of x is f(x) positive

kow [346]

Answer:

The function f(x) is positive in the interval (-≠,-2.5) ∪ (1,∞)

Step-by-step explanation:

we have

$f(x)=2x^{2}+3x-5$

This is a vertical parabola open upward (the leading coefficient is positive)

The vertex is a minimum

The coordinates of the vertex is the point (h,k)

step 1

Find the vertex of the quadratic function

Factor the leading coefficient 2

$f(x)=2(x^{2}+\frac{3}{2}x)-5$

Complete the square

$f(x)=2(x^{2}+\frac{3}{2}x+\frac{9}{16})-5-\frac{9}{8}$

$f(x)=2(x^{2}+\frac{3}{2}x+\frac{9}{16})-\frac{49}{8}$

Rewrite as perfect squares

$f(x)=2(x+\frac{3}{4})^{2}-\frac{49}{8}$

The vertex is the point (-\frac{3}{4},-\frac{49}{8})

step 2

Find the x-intercepts (values of x when the value of f(x) is equal to zero)

For f(x)=0

$2(x+\frac{3}{4})^{2}-\frac{49}{8}=0$

$2(x+\frac{3}{4})^{2}=\frac{49}{8}$

$(x+\frac{3}{4})^{2}=\frac{49}{16}$

take the square root both sides

$x+\frac{3}{4}=\pm\frac{7}{4}$

$x=-\frac{3}{4}\pm\frac{7}{4}$

$x_1=-\frac{3}{4}+\frac{7}{4}=1$

$x_2=-\frac{3}{4}-\frac{7}{4}=-2.5$

therefore

The function f(x) is negative in the interval (-2.5,1)

The function f(x) is positive in the interval (-≠,-2.5) ∪ (1,∞)

see the attached figure to better understand the problem

6 0

4 years ago

What is the value of z so that-9 and 9 are both solutions of x^2+z=103?

notka56 [123]

If the sol'ns are -9 and 9, then we can use this to form our eq'n:
(x - 9)(x + 9) = 0
x^2 - 81 = 0
so...
x^2 + z - 103 = x^2 -81
z - 103 = -81
z = -81 + 103
z = 22

8 0

3 years ago