Answer:
y=5x+3
Step-by-step explanation:
Hi there!
We're given the point (-1, -2) and a slope of 5. We need to find the equation of the line in slope intercept form.
Slope-intercept form is given as y=mx+b, where m is the slope and b is the y intercept
Since we're already given the slope, we can substitute that immediately into the equation
here it is so far:
y=5x+b
now we need to solve for b
Since the line will pass through the point (-1,-2), we can use it to solve for b
substitute -1 as x and -2 as y into the equation
-2=5(-1)+b
multiply
-2=-5+b
add 5 to both sides
3=b
substitute that into the equation
therefore, the equation of the line is <u>y=5x+3</u>
Hope this helps! :)
A toothbrush weighs that much. a paperclip weighs less then an ounce, about 0.049 oz.
have a nice day
<span>Answer:
Its too long to write here, so I will just state what I did.
I let P=(2ap,ap^2) and Q=(2aq,aq^2)
But x-coordinates of P and Q differ by (2a)
So P=(2ap,ap^2) BUT Q=(2ap - 2a, aq^2)
So Q=(2a(p-1), aq^2)
which means, 2aq = 2a(p-1)
therefore, q=p-1
then I subbed that value of q in aq^2
so Q=(2a(p-1), a(p-1)^2)
and P=(2ap,ap^2)
Using these two values, I found the midpoint which was:
M=( a(2p-1), [a(2p^2 - 2p + 1)]/2 )
then x = a(2p-1)
rearranging to make p the subject
p= (x+a)/2a</span>
When the rocket accelerates up, the thrust is greater than the combined lift and drag, therefore making it go upward. Thrust from the engine / or whatever the power source is makes it lift.
Hope that helps!
Answer: x < -2
Step-by-step explanation:
