First off, nicely done on the exponents. You'd be surprised on how bad some look ,:D
a)
![(3xy^{3})(2x^{2}y)\\ (3*2)(x*x^{2})(y^{3}*y)\\\\ 6x^{3}y^{4}](https://tex.z-dn.net/?f=%20%283xy%5E%7B3%7D%29%282x%5E%7B2%7Dy%29%5C%5C%20%283%2A2%29%28x%2Ax%5E%7B2%7D%29%28y%5E%7B3%7D%2Ay%29%5C%5C%5C%5C%206x%5E%7B3%7Dy%5E%7B4%7D%20)
b)
That equation can represent the relationship among the image distance,
object distance, and focal length of a lens.
It could describe the effective resistance of two resistors in parallel, the
effective inductance of two coils in parallel, or the effective capacitance
of two capacitors in series.
Thanks for sharing it. Now, did you have a question to ask ?
Answer: Answers are in the steps read carefully!
Step-by-step explanation:
A) 3x^2 - 7x + 2 To factor this polynomial, you have to find two numbers that their product is 6 and their sum is -7. The numbers -1 and -6 works out because -6 times -1 is 6 and -6 plus -1 is -7.
Now rewrite the polynomial as
3x^2 - 1x - 6x + 2 Now group it
(3x^2 - 1x) (-6x+2) Factor it by groups
x (3x -1) -2(3x -1) Now factor out 3x-1
(3x -1) (x-2) Done!
B) 2x^2 - x -3 Now the same way.You will have two numbers that their product is -6 and their sum is -1. You may be wondering how I get -6 .I get -6 by multiply the leading coefficient 2 by the constant -3. The numbers -3 and 2 works out. Because -3 times 2 is -6 and -3 plus 2 is -1.
Rewrite the polynomial as
2x^2 +2x - 3x -3 GRoup them and factor them
(2x^2 + 2x) (-3x-3)
2x(x+1) -3(x+1) Factor out x+1
(x+1) (2x -3) Done!
C) 3x^2 - 16x - 12 Find two numbers that their product is -36 and their sum is -12. The numbers -18 and 2 works out because -18 times 2 is -36 and -18 plus 2 is -16.
Rewrite the polynomial
3x^2 +2x -18x - 12 GRoup them
(3x^2 + 2x) (-18x - 12) Factor them
x (3x +2) -6(3x +2) Factor out 3x+2
(3x+2) (x -6) Done !
Answer:
27
Step-by-step explanation:
3².2³/2² + 3².2²/2² = 27