Message body weight 30 points

A 6.8 KG object moves with a velocity of 8 M/S what’s it's kinetic energy?

FromTheMoon [43]

Answer:

Explanation:

KE = ½mv² = ½(6.8)8² = 217.6 J

round as appropriate because that result is way too much precision for the inputs provided. Arguably should be 200 J based on the single significant digit of the velocity.

8 0

2 years ago

A wave has a wavelength of 7 mm and a frequency of 19 hertz. What is its speed?

ASHA 777 [7]

Speed = (frequency) x (wavelength)

Speed = (19 per second) x (7 mm)

Speed = (19 x 7) (per second · mm)

Speed = 133 mm/sec

or you might want to write Speed = 0.133 m/s .

4 0

3 years ago

An open pipe of length 0.58 m vibrates in the third harmonic with a frequency of 939Hz. What is the speed of sound through the a

vaieri [72.5K]

363 m/s is the speed of sound through the air in the pipe.

Answer: Option B

Explanation:

The formula used to calculate the wavelength given as below,

$Wavelength (\lambda)=\frac{\text { wave velocity }(v)}{\text { frequency }(f)}$

$v=\lambda \times f$ --------> eq. 1

In power system, harmonics define by positive integers of the fundamental frequency. So the third order harmonic is a multiple of the third fundamental frequency. Each harmonic creates an additional node and an opposite node, as well as an additional half wave within the string.

If the number of waves in the circuit is known, the comparison between standing wavelength and circuit length can be calculated algebraically. The general expression for this given as,

$L=\frac{n \lambda}{2}$

For first harmonic, n =1

$L=\frac{\lambda}{2}$

For second harmonic, n =2

$L=\frac{2 \lambda}{2}=\lambda$

For third harmonic, n =3

$L=\frac{3 \lambda}{2}$

$\lambda=\frac{2 L}{3}$ -------> eq. 2

Here given f = 939 Hz, L = 0.58 m...And, substitute eq 2 in eq 1 and values, we get

$v=\frac{2 \times 0.58 \times 989}{3}=\frac{1089.24}{3}=363.08 \mathrm{m} / \mathrm{s}$

3 0

3 years ago

What is system thinking ?

Greeley [361]

Answer: Systems thinking is a holistic approach to analysis that focuses on the way that a system's constituent parts interrelate and how systems work over time and within the context of larger systems.

7 0

3 years ago

Measure the distance from the drop point in Brazil to the drop point in Angola. Use that number in your calculation. Given that

klemol [59]

To develop this point we will start by finding the approximate coordinates of the points that were connected at the time of the Pangaea between Brazil and Angola. These coordinates are presented below.

1 . Brazil - Latitude: 18 0 07’ 55.56” S Longitude: 39 0 35’ 14.50” W 2.

Angola - Latitude: 9 0 08’ 50.02” S Longitude: 13 0 02’ 32.11” E

Using a tool for calculating distances between these two points we will notice that its distance is 576,155,570.12 cm

Applying the equation given in the statement we will have to,

$v = \frac{x}{t} \rightarrow v = Velocity, x = Distance, t = Time$

200,000,000 years have passed and the movement was previously found, so the speed of travel is,

$v = \frac{576,155,570.12cm}{200.000.000 years}$

$v = 2.88 cm/year$

Therefore the velocity is 2.88 cm per year.

6 0

3 years ago