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Levart [38]
3 years ago
8

A 2.26 kg book is dropped from a height 1.5m what is its acceleration

Physics
1 answer:
Arada [10]3 years ago
4 0
The answer is 9.8 ms^-2, because there is only one force acting on the object so the acceleration will be numerically equal to the gravitational field strength.
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Identify each unit as belonging to SI units or US Customary units.
torisob [31]

Answer:

<em>SI Units</em>

              Meter

              Kilogram

              Kelvin

<em>US Customary Units and English Units</em>

              Gallon

              Mile

              Pound

              Degrees Fahrenheit

Explanation:

The SI units or International System of Units are the widely used metrics of measuring a physical quantity. It has specific abbreviations.

The US customary units is a measurement system where it is widely used in the united states. This system of unit also has abbreviations.

There are also conversion scales that are used to convert a unit from one metric system to the other.

For example, the conversion of mile to SI unit is given by the formula

                             1 mile = 1609.4 meters

Similarly,                

                             1 pound = 0.453592 Kg

6 0
3 years ago
The nebula hypothesis of the formation of the solar system assumes that the material that became the solar system began as a lar
Zinaida [17]

Answer:

Option (D)

Explanation:

According to the nebula hypothesis that explains the formation of solar system, there occurs changes in terms of its shape as well as the rate of rotation. It is because of the conservation of angular momentum.

The total angular momentum comprising a system remains same or constant, throughout its period of rotation in the absence of net torque. Due to the increasing density, the nebula eventually collapses, and these clouds of gases collides with one another and forms a large cloud. These clouds attains an average velocity and results in an orderly motion, which eventually take the shape of a disk. This is how with time, the sun and the planets have formed, comprising the solar system.

Thus, the correct answer is option (D).

6 0
3 years ago
The direction of current in a solenoid depends on the direction of magnetic field’. Do you agree with this statement? Showthe pa
iogann1982 [59]

Answer:

1) Yes the direction of the magnetic field is found based on Fleming's Right Hand Rule

2) The pattern indicates the direction of the magnetic force field lines

Explanation:

1) The solenoid is the is the coil of electric conductor that when it carries an electric current produces a magnetic field

According to Fleming's Right Hand Rule, the direction of the magnetic field produced by a solenoid, depends on the direction of the current such that when the direction of the conventional current is in the direction of the wrapped fingers, the thumb points in the direction of the magnetic field which is North N.

2) The pattern of field lines inside the solenoid indicates the direction of the generated magnetic field moving from left to right within the solenoid as the electric current moves around in the direction shown in the diagram.

7 0
3 years ago
6) The length of year is equal to the time it takes for one *
QveST [7]

Answer:

C: revolution of the Earth around the Sun

Explanation:

8 0
2 years ago
Two tiny particles having charges 20.0 μC and 8.00 μC are separated by a distance of 20.0 cm What are the magnitude and directio
Alecsey [184]

Answer:

The magnitude and direction of electric field midway between these two charges is 10.8\times10^{5}\ N/C along AB.

Explanation:

Given that,

First charge q_{1}= 20\mu C

second charge q_{2}= 8\mu C

Distance = 20 cm

We need to calculate the electric field

For first charge,

Using formula of electric field

E_{1}= \dfrac{kq_{1}}{r^2}

Put the valueinto the formula

E_{1}=\dfrac{9\times10^{9}\times20\times10^{-6}}{10\times10^{-2}}

E_{1}=18\times10^{5}\ N/C

Direction of electric field along AB

We need to calculate the electric field

For second charge,

Using formula of electric field

E_{2}= \dfrac{kq_{2}}{r^2}

Put the valueinto the formula

E_{2}=\dfrac{9\times10^{9}\times8\times10^{-6}}{10\times10^{-2}}

E_{2}=7.2\times10^{5}\ N/C

Direction of electric field along AO

We need to calculate the net electric field at midpoint

E_{net}=E_{1}-E_{2}

E_{net}=(18-7.2)\times10^{5}\ N/C

E_{net}=10.8\times10^{5}\ N/C

Direction of net electric field along AB

Hence, The magnitude and direction of electric field midway between these two charges is 10.8\times10^{5}\ N/C along AB.

8 0
3 years ago
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