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Aleks04 [339]
3 years ago
11

Based on the results from this experiment, predict whether some of the following combinations of compounds would precipitate or

stay in solution. Explain how you determined that a certain compound should precipitate or be soluble. a. LiOH NaCl b. BaCl2 Na3PO4 c. MgSO4 KOH
Chemistry
1 answer:
iren [92.7K]3 years ago
6 0

Answer:

* No precipitate: LiOH(aq)+NaCl(aq)\rightarrow LiCl(aq)+NaOH(aq)

* Precipitate: 3BaCl_2(aq) +2Na_3PO_4(aq) \rightarrow Ba_3(PO_4)_2(s)+6NaCl(aq)

* Precipitate: MgSO_4(aq)+2KOH(aq)\rightarrow Mg(OH)_2(s)+K_2SO_4(aq)

Explanation:

Hello!

In this case, since these all are double displacement reactions, in which the cations and anions are exchanged, we can write the resulting chemical reactions as follows:

a. LiOH and NaCl: No precipitate is formed since LiOH and NaOH are both largely soluble in water:

LiOH(aq)+NaCl(aq)\rightarrow LiCl(aq)+NaOH(aq)

b. BaCl2 and Na3PO4: barium phosphate precipitate is formed because it has a large molar mass which makes it insoluble in water:

3BaCl_2(aq) +2Na_3PO_4(aq) \rightarrow Ba_3(PO_4)_2(s)+6NaCl(aq)

c. MgSO4 and KOH: magnesium hydroxide "milky" precipitate is formed because it is not soluble in water:

MgSO_4(aq)+2KOH(aq)\rightarrow Mg(OH)_2(s)+K_2SO_4(aq)

Moreover, we can relate the solubility of a substance by considering its polarity, molar mass and nature; usually, heavy substances tend to be insoluble in water as well as nonpolar compounds.

Best regards!

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Alchemists in the Middle Ages dreamed of converting base metals, such as lead, into precious metals—gold and silver. Why could t
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Explanation:

Each element in the periodic table has different but fixed number of the protons in nucleus of it's atom, which is known as the atomic number.

Transmutation of one chemical element into the another involves the changing of the atomic number. Such nuclear reaction requires millions of the times more energy as compared to normal chemical reactions. Thus, the dream of  the alchemist of transmuting the lead into the gold was never achievable chemically .

Conversion of lead to gold in today's world:

This conversion is indeed possible. The requirements are a particle accelerator, tremendous supply of the energy. Nuclear scientists at the Lawrence Berkeley National Laboratory located in California, more than 30 years ago, succeeded in producing very minute amounts of the gold from the bismuth. Bismuth is a metallic element which is adjacent to the lead on periodic table. Same process would work for the lead but isolating gold at end of reaction would prove much more difficult because lead is available in many isotopes. The homogeneous nature of the element means that it is easier to separate the gold from the bismuth as compared to separate the gold from the lead which has four  isotopic identities which all are stable.

4 0
3 years ago
A valid lewis structure of ________ cannot be drawn without violating the octet rule.
luda_lava [24]
A valid lewis structure of SO2 cannot be drawn without violating the octet rule.



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3 years ago
6.(01.05 LC) Which states of matter change shape when moved?(2 points) Gases and solids Liquids and gases Liquids, solids, and g
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4 years ago
In each reaction box place the best reagent and conditions from the list below benzene 3 boxes
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Answer : The correct answer is 1) AlCl₃ - CH₃Cl 2) HNO₃ -H₂SO₄ at room temperature 3) Fuming HNO₃ -H₂SO₄ at 90-100 ⁰ C heat .

I think this reaction is forming 2,4,6- trinitrotoluene from benzene, since the product is not mentioned. Following are the steps to convert Benzene to 2,4,6 trinitrotoluene .

Step 1: Conversion of Benzene to Toluene .

Benzene can be converted to toluene by Friedel Craft Alkylation of benzene . In this reaction reagent AlCl₃ and Ch3Cl is used . Electrophile CH³⁺ is produced which attached on carbon of benzene and formation of Toluene and HCl occur.

Benzene     \frac{AlCl3}{Ch3Cl}>   Toulene + HCl

Step 2 : Conversion of Toluene to dinitrotoluene.

Dinitritoluene is prepared from toluene by Nitration . This reaction uses Electrophilic substitution mechanism . The reagents used are HNO₃ and H₂SO₄ at room temperature . These reagents produces NO₂⁺ ( nitronium ion ), a electrophile which attacks on C2 and C4 Carbon atoms of Toluene.

Toluene Tolune   \frac{HNO3 -H2SO4}{30-40 degree C} ->  2,4- dinitrotoluene

Step 3) Conversion of Dinitro toluene to trinitrotoluene.

This reaction is extended nitration of toluene . Further nitration is done in extreme condition . The temperature of reaction is increased to 90- 100 ⁰ C . Due to which there is more production of NO²⁺ ion occurs from HNO₃ -H₂SO₄ and they attack on C6 carbon atom of dinitrotoluene which forms 2,4,6- trinitrotoluene.

Dinitrotoluene 2,4 -dinitrotoluene   \frac{fuming HNO3-H2So4}{90-100 C} ->  2,4,6-trinitrotoluene.

So over all reaction uses three reagents in order :

Benzene  \frac{AlCl3}{CH3Cl}  -> Toluene  \frac{HNO3-H2So4}{room temp}  -> 2,4-dinitrotoluene  \frac{Fuming HNO3 -H2SO4}{Heating at 90-100 C}  -> 2,4,6-trinitrotoluene .

3 0
4 years ago
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