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Juliette [100K]
2 years ago
11

A boy is being pushed on a swing. His older sister with a greater mass sits on the swing next. Which statement describes the cha

nge in motion if his sister is pushed with the same force?
Chemistry
2 answers:
anastassius [24]2 years ago
7 0
If the same force is exerted and she weighs more, her acceleration would be lesser than the brothers because a heavier object takes more time to accelerate when the same force is exerted.
Troyanec [42]2 years ago
3 0

Answer:

yes he forced up then avoid it

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Which of the following statements best compares the pH value of H3PO4 and HCl?
wel

Answer:

Option B. Both have a pH less than 7, but H3PO4 has a lower pH than HCl

Explanation:

Those are acid, so the pH would be < 7.

H₃PO₄ is a weak acid with 3 dissociations

HCl is a strong acid.

pH depends on [H]⁺

H₃PO₄  →  3H⁺  +  PO₄⁻³

HCl →  H⁺  +  Cl⁻

If both acid, have the same concentration, [H⁺]H₃PO₄ > [H⁺]HCl, that's why the pH from the phosphoric will be lower.

5 0
3 years ago
A piece of wood has a labeled length value of 63.2 cm. You measure its length three times and record the following data: 63.1 cm
Ulleksa [173]

Percent error (%)= \frac{\left | Accepted value - Measured value \right |}{Accepted value}\times 100

Accepted value is true value.

Measured values is calculated value.

In the question given Accepted value (true value) = 63.2 cm

Given Measured(calculated values) = 63.1 cm , 63.0 cm , 63.7 cm

1) Percent error (%) for first measurement.

Accepted value (true value) = 63.2 cm, Measured(calculated values) = 63.1 cm

Percent error (%)= \frac{\left | Accepted value - Measured value \right |}{Accepted value}\times 100

Percent error = \frac{\left | 63.2 - 63.1 \right |}{63.2}\times 100

Percent error = \frac{0.1}{63.2}\times 100

Percent error = 0.00158\times 100

Percent error = 0.158 %

2) Percent error (%) for second measurement.

Accepted value (true value) = 63.2 cm, Measured(calculated values) = 63.0 cm

Percent error (%)= \frac{\left | Accepted value - Measured value \right |}{Accepted value}\times 100

Percent error = \frac{\left | 63.2 - 63.0 \right |}{63.2}\times 100

Percent error = \frac{0.2}{63.2}\times 100

Percent error = 0.00316\times 100

Percent error = 0.316 %

3) Percent error (%) for third measurement.

Accepted value (true value) = 63.2 cm, Measured(calculated values) = 63.7 cm

Percent error (%)= \frac{\left | Accepted value - Measured value \right |}{Accepted value}\times 100

Percent error = \frac{\left | 63.2 - 63.7 \right |}{63.2}\times 100

Percent error = \frac{\left | -0.5 \right |}{63.2}\times 100

Percent error = \frac{(0.5)}{63.2}\times 100

Percent error = 0.00791\times 100

Percent error = 0.791 %

Percent error for each measurement is :

63.1 cm = 0.158%

63.0 cm = 0.316%

63.7 cm = 0.791%




7 0
3 years ago
An ideal gas has a volume of 5.00L under a pressure of 1.00 atm and a temperature of 10.0 K. If the temperature is changed to 10
tigry1 [53]

Answer:

6.25 L

Explanation:

Please see the step-by-step solution in the picture attached below.

Hope this answer can help you. Have a nice day!

7 0
3 years ago
Explain the differences between bronze and brass, and steel and cast iron. Which is best used for cooking wares?
Dennis_Churaev [7]

Answer:

Steel and cast iron

Explanation:

They are all metal but assuming that you are finding the best material for your pan i suggest going for steel or cast iron

8 0
3 years ago
How many milliliters of 0.0050 N KOH are required to neutralize 41 mL of 0.0050 M H2SO4?
Kipish [7]

Answer:

V KOH = 41 mL

Explanation:

for neutralization:

  • ( V×<em>C </em>)acid = ( V×<em>C </em>)base

∴ <em>C </em>H2SO4 = 0.0050 M = 0.0050 mol/L

∴ V H2SO4 = 41 mL = 0.041 L

∴ <em>C</em> KOH = 0.0050 N = 0.0050  eq-g/L

∴ E KOH = 1 eq-g/mol

⇒ <em>C</em> KOH = (0.0050 eq-g/L)×(mol KOH/1 eq-g) = 0.0050 mol/L

⇒ V KOH = ( V×<em>C </em>) acid / <em>C </em>KOH

⇒ V KOH = (0.041 L)(0.0050 mol/L) / (0.0050 mol/L)

⇒ V KOH = 0.041 L

4 0
3 years ago
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