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Sonja [21]
3 years ago
8

A land owner is planning to build a fenced-in, rectangular patio behind his garage, using his garage as one of the "walls." He w

ants to maximize the area using 80 feet of fencing. The quadratic function A(x)=x(80−2x) gives the area of the patio, where x is the width of one side. Find the maximum area of the patio.
Mathematics
1 answer:
GrogVix [38]3 years ago
3 0

Answer:  800 feet²

Step-by-step explanation:

Lets remove the brackets from the function's expression

A(x) = -2x²+80x

So we got the quadratic function and we have to find the x that corresponds to function's maximum. Let it be X max

As we know Xmax= (X1+X2)/2 , where X1 and X2 are the roots of the function A(x)

Lets find X1 and X2

x(80-2x)=0

x1=0   80-2*X2=0

x2=40

So Xmax= (0+40)/2=20

So Amax= A(20)= 20*(80-2*20)=20*40=800 feet²

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Given the following signal:  x(n) = {4, −1, 2, 5, − 2, 3}  Compute the 6-point DFT of x(n) directly from the DFT equation  −
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Answer:

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x(1) = 21/8 -j13/8

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Step-by-step explanation:

See the picture for workings.

Given X(n) = { 4, -1, 2, 5, -2, 3}

Six point DFT implies that N = 6

Step 1 = write out equation X(k)

Step 2 = substitute "Wn" in the equation X(k) to give a new equation

Step 3 = when N=6, substitute for "N" in the new equation and simplify the new X(k) equation.

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