How many grams of Fe are needed to create 32.5mol Fe3O4?
1 answer:
Answer:
5444.89 grams of Fe
Explanation:
1) We need the chemical equation for Fe3O4 to find the mole ratio for Fe to Fe3O4. Chemical equation:
3Fe+4H2O → Fe3O4+4H2
The mole ratio of Fe to Fe3O4 is 3:1
2) Now, we find how many grams of Fe are needed to produce 32.5 moles of Fe3O4.
= 97.5 moles Fe needed to produce 32.5 moles of Fe3O4
3) Convert 97.5 moles of Fe into grams. The molar mass of Fe is 55.845g.
= 5444.8875g or 5444.89g.
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Answer:
Here's what I get.
Explanation:
The MO diagrams of KrBr, XeCl, and XeBr are shown below.
They are similar, except for the numbering of the valence shell orbitals.
Also, I have drawn the s and p orbitals at the same energy levels for both atoms in the compounds. That is obviously not the case.
However, the MO diagrams are approximately correct.
The ground state electron configuration of KrF is
KrF⁺ will have one less electron than KrF.
You remove the antibonding electron from the highest energy orbital, so the bond order increases.
The KrF bond will be stronger.
