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leva [86]
3 years ago
9

How many grams of Fe are needed to create 32.5mol Fe3O4?

Chemistry
1 answer:
Mademuasel [1]3 years ago
5 0

Answer:

5444.89 grams of Fe

Explanation:

1) We need the chemical equation for Fe3O4 to find the mole ratio for Fe to Fe3O4. Chemical equation:

3Fe+4H2O → Fe3O4+4H2

The mole ratio of Fe to Fe3O4 is 3:1

2) Now, we find how many grams of Fe are needed to produce 32.5 moles of Fe3O4.

32.5 moles Fe3O4x \frac{4 mole O}{1 mole Fe3O4} = 97.5 moles Fe needed to produce 32.5 moles of Fe3O4

3) Convert 97.5 moles of Fe into grams. The molar mass of Fe is 55.845g.

97.5 mole Fex\frac{55.845g Fe}{1 mole Fe} = 5444.8875g or 5444.89g.

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04.05 mol
victus00 [196]

Answer:

34.8 g

Explanation:

Answer:

We have the masses of two reactants, so this is a limiting reactant problem.

We will need a balanced equation with masses, moles, and molar masses of the compounds involved.

1. Gather all the information in one place with molar masses above the formulas and masses below them.  

Mᵣ:         123.90    70.91      208.24

                 P₄   +   20Cl₂ ⟶ 4PCl₅

Mass/g:   46.0       32.0

2. Calculate the moles of each reactant  

\text{moles of P}_{4} = \text{46.0 g P}_{4} \times \dfrac{\text{1 mol P}_{4}}{\text{123.90 g P}_{4}} = \text{0.3713 mol P}_{4}\\\\\text{moles of Cl}_{2} = \text{32.0 g Cl }_{2} \times \dfrac{\text{1 mol Cl }_{2}}{\text{70.91 g Cl }_{2}} = \text{0.4513 mol Cl }_{2}

3. Calculate the moles of PCl₅ we can obtain from each reactant

From P₄:

The molar ratio is 4 mol PCl₅:4 mol P₄

\text{Moles of PCl}_{5} = \text{0.3713 mol P}_{4} \times \dfrac{\text{4 mol PCl}_{5}}{\text{4 mol P}_{4}} = \text{0.3713 mol PCl}_{5}

From Cl₂:

The molar ratio is 4 mol PCl₅:20 mol Cl₂

\text{Moles of PCl}_{5} =  \text{0.4513 mol Cl}_{2}\times \dfrac{\text{4 mol PCl}_{5}}{\text{20 mol Cl}_{2}} = \text{0.090 26 mol PCl}_{5}

4. Identify the limiting and excess reactants

The limiting reactant is chlorine, because it gives the smaller amount of PCl₅.

The excess reactant is phosphorus.

5. Mass of excess reactant

(a) Moles of P₄ reacted

The molar ratio is 1 mol P₄:20 mol Cl₂

\text{Moles reacted} = \text{0.4513 mol Cl}_{2} \times \dfrac{\text{4 mol P}_{4}}{\text{20 mol Cl}_{2}} = \text{0.090 26 mol P}_{4}

(b) Mass of P₄ reacted

\text{Mass reacted} = \text{0.090 26 mol P}_{4} \times \dfrac{\text{123.90 g P}_{4}}{\text{1 mol P}_{4}} = \text{11.18 g P}_{4}

(c) Mass of P₄ remaining

Mass remaining = original mass – mass reacted = (46.0 - 11.18) g = 34.8 g P₄

4 0
3 years ago
Which of the following chemicals can damage the central nervous system, cardiovascular system, reproductive system, hematologica
weeeeeb [17]
Answer : Option B) Lead

Explanation : Lead is chemical element which damages<span> the central nervous system, cardiovascular system, reproductive system, hematological system, and kidneys with overexposure as compared to other elements in the given option.</span>
6 0
3 years ago
Read 2 more answers
A molecule of ethyl alcohol is converted to acetaldehyde in one’s body by zero order kinetics. If the concentration of alcohol i
Oliga [24]

Answer:

(1) 0.0016 mol/L

Explanation:

Let the concentration of alcohol after 3.5 hours be y M

The reaction follows a first-order

Rate = ky^0 = change in concentration/time

k = 6.4×10^-5 mol/L.min

Initial concentration = 0.015 M

Concentration after 3.5 hours = y M

Time = 3.5 hours = 3.5×60 = 210 min

6.4×10^-5y^0 = 0.015-y/210

y^0 = 1

0.015-y = 6.4×10^-5 × 210

0.015-y = 0.01344

y = 0.015 - 0.01344 = 0.00156 = 0.0016 mol/L (to 4 decimal places)

5 0
3 years ago
Please help me ASAP
pantera1 [17]
CH4 + 2O2 -> 2H2O + CO2

You need to add a 2 in front of the O2 and H2O in order to balance the equation.
6 0
3 years ago
Explain why crystallisation can't be used to prepare calcium carbonate.​
liq [111]

Explanation:

The mechanisms by which amorphous intermediates transform into crystalline materials are poorly understood. Currently, attracting enormous interest is the crystallization of amorphous calcium carbonate, a key intermediary in synthetic, biological, and environmental systems. Here we attempt to unify many contrasting and contradictory studies by investigating this process in detail. We show that amorphous calcium carbonate can dehydrate before crystallizing, both in solution and in air, while thermal analyses and solid-state nuclear magnetic resonance measurements reveal that its water is present in distinct environments. Loss of the final water fraction—comprising less than 15% of the total—then triggers crystallization. The high activation energy of this step suggests that it occurs by partial dissolution/recrystallization, mediated by surface water, and the majority of the particle then crystallizes by a solid-state transformation. Such mechanisms are likely to be widespread in solid-state reactions and their characterization will facilitate greater control over these processes.

4 0
3 years ago
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