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2 years ago

How many grams of Fe are needed to create 32.5mol Fe3O4?

Chemistry

1 answer:

Mademuasel [1]2 years ago

5 0

Answer:

5444.89 grams of Fe

Explanation:

1) We need the chemical equation for Fe3O4 to find the mole ratio for Fe to Fe3O4. Chemical equation:

3Fe+4H2O → Fe3O4+4H2

The mole ratio of Fe to Fe3O4 is 3:1

2) Now, we find how many grams of Fe are needed to produce 32.5 moles of Fe3O4.

$32.5 moles Fe3O4$ $x \frac{4 mole O}{1 mole Fe3O4}$ = 97.5 moles Fe needed to produce 32.5 moles of Fe3O4

3) Convert 97.5 moles of Fe into grams. The molar mass of Fe is 55.845g.

$97.5 mole Fe$ $x\frac{55.845g Fe}{1 mole Fe}$ = 5444.8875g or 5444.89g.

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Answer:

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Explanation:

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1.56 δ (4H, triplet) - (-CH₂-CH₂-CH-OH) ; triplet as coupling with 2 H,

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