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leva [86]
3 years ago
9

How many grams of Fe are needed to create 32.5mol Fe3O4?

Chemistry
1 answer:
Mademuasel [1]3 years ago
5 0

Answer:

5444.89 grams of Fe

Explanation:

1) We need the chemical equation for Fe3O4 to find the mole ratio for Fe to Fe3O4. Chemical equation:

3Fe+4H2O → Fe3O4+4H2

The mole ratio of Fe to Fe3O4 is 3:1

2) Now, we find how many grams of Fe are needed to produce 32.5 moles of Fe3O4.

32.5 moles Fe3O4x \frac{4 mole O}{1 mole Fe3O4} = 97.5 moles Fe needed to produce 32.5 moles of Fe3O4

3) Convert 97.5 moles of Fe into grams. The molar mass of Fe is 55.845g.

97.5 mole Fex\frac{55.845g Fe}{1 mole Fe} = 5444.8875g or 5444.89g.

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2 years ago
Propane gas, C3H8, is sometimes used as a fuel. In order to measure its energy output as a fuel a 1.860 g sample was combined wi
lisov135 [29]

Answer:

The heat of the reaction is 105.308 kJ/mol.

Explanation:

Let the heat released during reaction be q.

Heat gained by water: Q

Mass of water ,m= 1kg = 1000 g

Heat capacity of water ,c= 4.184 J/g°C

Change in temperature = ΔT = 26.061°C - 25.000°C=1.061 °C

Q=mcΔT

Heat gained by bomb calorimeter =Q'

Heat capacity of bomb calorimeter ,C= 4.643 J/g°C

Change in temperature = ΔT'= ΔT= 26.061°C - 25.000°C=1.061 °C

Q'=CΔT'=CΔT

Total heat released during reaction is equal to total heat gained by water and bomb calorimeter.

q= -(Q+Q')

q = -mcΔT - CΔT=-ΔT(mc+C)

q=-1.061^oC(1000 g\times 4.184J/g^oC+4.643 J/^oC )=-4,444.15J=-4.444 kJ

Moles of propane =\frac{1.860 g}{44 g/mol}=0.0422 mol

0.0422 moles of propane on reaction with oxygen releases 4.444 kJ of heat.

The heat of the reaction will be:

\frac{4.444 kJ}{0.0422 mol}=105.308 kJ/mol

3 0
3 years ago
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