Answer:
Explanation:
Hello!
In this case, we can divide the problem in two steps:
1. Dilution to 278 mL: here, the initial concentration and volume are 1.20 M and 52.0 mL respectively, and a final volume of 278 mL, it means that the moles remain the same so we can write:
So we solve for C2:
2. Now, since 111 mL of water is added, we compute the final volume, V3:
So, the final concentration of the 139 mL portion is:
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Answer:
H3PO4 + 3KOH ----> K3PO4 + 3H2O
Explanation:
The valency of K element is + 1 while that of PO4 compound is -3
Hence, at least 3 K atoms are needed to combine with PO4 to form K3PO4 compound.
Hence, the revised equation will be
H3PO4 + 3KOH ----> K3PO4 + 3H2O
Now, the number of atoms and charges of each element is a given equation are equal on both the left and right hand side.
Answer:
957.7mL
Explanation:
Using the formula below;
CaVa = CbVb
Where;
Ca = concentration of acid (M)
Va = volume of acid (mL)
Cb = concentration of base (M)
Vb = volume of base (mL)
According to the information provided in this question:
Ca = 0.166 M
Cb = 0.013 M
Va = 75mL
Vb = ?
Using CaVa = CbVb
0.166 × 75 = 0.013 × Vb
12.45 = 0.013Vb
Vb =12.45/0.013
Vb = 957.7mL
Use the state equation for ideal gases: pV = nRT
Data:
V = 88.89 liter
n = 17 mol
T = 67 + 273.15 = 340.15 K
R = 0.0821 atm * liter / (K*mol)
=> p = nRT / V = 17 mol * 0.0821 (atm*liter / K*mol) * 340.15 K / 88.89 liter
p = 5.34 atm
Answer: p = 5.34 atm
