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Pani-rosa [81]
3 years ago
10

First, what are the characteristics of a population for which it would be appropriate to use mean/median/mode? When would the ch

aracteristics of a population make them inappropriate to use? Second, using your own experience, what problems have you encountered when you were asked to solve a problem that required gathering and analyzing data? Describe the scenario. What challenges did you face and how did you address the challenges?
Mathematics
1 answer:
pochemuha3 years ago
8 0

Answer:

A population in which the characteristic of interest is a discrete or continuous quantitative variable with an approximately symmetric and meso-curt distribution is appropriate to use the mean.

A population in which the characteristic of interest is a discrete or continuous quantitative variable with a slightly symmetric distribution or with extreme values ​​is appropriate to use the median.

A population in which the characteristic of interest is a qualitative variable is appropriate to use fashion.

It is not appropriate to use the mean if extreme values ​​are present.

It is not appropriate to use the median if there are several different values ​​with high frequency.

It is not appropriate to wear fashion if the distribution is very skewed asymmetrically.

A frequent problem arises when it is desired to establish the sampling frame, that is, a list of the individuals in the population.

Example: Establish the characteristics of households with children under two years. It was solved by sampling in two phases, identifying in a first phase the sampling frame.

Step-by-step explanation:

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How does the graph y=3^x compare to the graph y=3^-x
LUCKY_DIMON [66]

Answer:

Y = 3x^x is a graph that has exponential growth while y = 3^-x has exponential decay.

Y = 3x^x (-∞, 0) and (∞, ∞).

Y = 3x^-x (-∞, ∞) and (∞, 0).

Step-by-step explanation:

The infinity symbols were being used to represent the x and y values of each graph. I will call y = 3^x "graph 1" and y = 3^-x "graph 2".

When graph 1 had positive ∞ for its x value, its y value was reaching towards positive ∞. When its x was reaching for negative ∞, its y was going for 0.

For graph 2, however, when its x was reaching for positive ∞, its x was reaching for 0. When its x was reaching for negative ∞, its y was going for positive ∞.

Here's an image of the graphs:

5 0
3 years ago
Divide using synthetic division.<br> (k + k4 - 28kº - 12k+ 17k - 40) : (k - 5)
Alex_Xolod [135]

Answer:

3

Step-by-step explanation:

5 0
3 years ago
Plez help! it would be much appreciated! :&gt;
Kaylis [27]

Answer: the 3rd graph cause the other are in the middle well close if that didn't help then i am so sorry if i did plz mark me Brainliest  

Step-by-step explanation:

6 0
3 years ago
How to solve these equations?
Scorpion4ik [409]
1) / sin x / = y ≥ 0 ;
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Then, / sin x / = 1 ;
sinx = + 1 or sin x = - 1 ;
x ∈ { 90 }  U { 270 } ;
x ∈  {90 , 270}.
8 0
3 years ago
When working with scientific notation, what does a negative exponent let you know about the size of the number?
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3 years ago
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