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Elanso [62]
2 years ago
13

How would you classify the number 125?

Mathematics
2 answers:
lys-0071 [83]2 years ago
4 0
125 = 5 * 5 * 5 = 5^3

Its a perfect cube.
AVprozaik [17]2 years ago
3 0

Answer:

Its a perfect cube.

Step-by-step explanation:

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To find three consecutive odd integers that have a sum of 63
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 Three consecutive odd integers that have a sun og 63 would be 23, 11, 29
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If A ⊂ B, then A ∩ B = ∅. <br> true<br> false
Aloiza [94]

Answer: false

Step-by-step explanation:

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2 years ago
A betta fish tank is in the shape of a cube. The volume of the fish tank is 216
GarryVolchara [31]

To find this answer, we need to understand how to get the Volume.

We get the volume by the formula: L x W x H

L = Length

W = Width

H = Height

So, we can see that there are 3 units required to know for getting the volume, if that's true, then, to do the inverse operation of finding the volume. That can be done by using thie formula:

V=a^3

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Solving for a

a=V⅓=216⅓=6

<h2>So hence, each of the Cube shaped Fish Tank is 6in³</h2>

now, let's look at how to find whether our answer is right or wrong

6x6=36

36x6=216

So hence, our answer is right!

-------------------------------------------------------------------------------------------------------"The beautiful thing about learning is that no one can take it away from you!" B.B.King

Thanks!

Mark me brainliest!

Have a GREAT AWESOME day!

~ms115~

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6 0
2 years ago
What's the volume of this composite fuigure.​
Eddi Din [679]
3.14(radius)squared(height)(3)
3.14(9)(8)(3)
3.14(72)(3)
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678.24
4 0
2 years ago
Which of the following is not a property of a chi-square distribution?
laiz [17]

Answer:

c) Is not a property (hence (d) is not either)

Step-by-step explanation:

Remember that the chi square distribution with k degrees of freedom has this formula

\chi_k^2 = \matchal{N}_1^2 +  \matchal{N}_2^2 + ... + \, \matchal{N}_{k-1}^2 +  \matchal{N}_k^2

Where N₁ , N₂m .... N_k are independent random variables with standard normal distribution. Since it is a sum of squares, then the chi square distribution cant take negative values, thus (c) is not true as property. Therefore, (d) cant be true either.

Since the chi square is a sum of squares of a symmetrical random variable, it is skewed to the right (values with big absolute value, either positive or negative, will represent a big weight for the graph that is not compensated with values near 0). This shows that (a) is true

The more degrees of freedom the chi square has, the less skewed to the right it is, up to the point of being almost symmetrical for high values of k. In fact, the Central Limit Theorem states that a chi sqare with n degrees of freedom, with n big, will have a distribution approximate to a Normal distribution, therefore, it is not very skewed for high values of n. As a conclusion, the shape of the distribution changes when the degrees of freedom increase, because the distribution is more symmetrical the higher the degrees of freedom are. Thus, (b) is true.

6 0
3 years ago
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