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Gala2k [10]
3 years ago
9

Why is a bowling ball harder to lift than a basket ball? Is it bc a bowling ball is made of metal?

Chemistry
1 answer:
vagabundo [1.1K]3 years ago
5 0
It is more slippery, and it is heavier
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If you have a gold brick that is 2cm by 3cm by 4cm and has density of 19.3g/cm3, what is its mass?
natulia [17]
Volume = a x a x a  

V = 2 cm x 3 cm x 4 cm => 24 cm³

Density = 19.3 g/cm³

Mass = ?

Therefore:

m = D x V

m = 19.3 x 24

m = 463.2 g
4 0
3 years ago
The (triangle)Hrxn of formation of carbon dioxide is negative. Which statement is true? The reaction is endothermic. The reactio
ANEK [815]
The negative ion reactions that consist of the formation of carbon dioxide in the atmosphere is generally an exothermic reaction. By definition, an exothermic reaction takes place when the chemical process eventually releases heat as its by-product. It is in contrast in endothermic process wherein heat is absorbed.
7 0
3 years ago
Read 2 more answers
A method used by the U.S. Environmental Protection Agency (EPA) for determining the concentration of ozone in air is to pass the
baherus [9]

Answer: 1. 9.08\times 10^{-6} moles

2. 90 mg

Explanation:

O_3(g)+2NaI(aq)+H_2O(l) \rightarrow O_2(g)+I_2(s)+2NaOH(aq)

According to stoichiometry:

1 mole of ozone is removed by 2 moles of sodium iodide.

Thus 4.54 \times 10^{-6} moles of ozone is removed by =\frac{2}{1}\times 4.54 \times 10^{-6}=9.08\times 10^{-6} moles of sodium iodide.

Thus 9.08\times 10^{-6} moles of sodium iodide are needed to remove 4.54\times 10^{-6} moles of O_3

2. \text{Number of moles of ozone}=\frac{0.01331g}{48g/mol}=0.0003moles

According to stoichiometry:

1 mole of ozone is removed by 2 moles of sodium iodide.

Thus 0.0003 moles of ozone is removed by =\frac{2}{1}\times 0.0003=0.0006 moles of sodium iodide.

Mass of sodium iodide= moles\times {\text {molar mass}}=0.0006\times 150g/mol=0.09g=90mg    (1g=1000mg)

Thus 90 mg of sodium iodide are needed to remove 13.31 mg of O_3.

3 0
3 years ago
For the reaction C + 2H2 → CH4, how many grams of hydrogen are required to produce 13.1 moles of methane, CH4 ?
BARSIC [14]

Answer:

7.0

Explanation:

7 0
3 years ago
Given that the density of iron is 7.9 g/cm3, what would be the volume of a 15.8 g piece of iron
Anuta_ua [19.1K]

Answer:

2cm^3

Explanation:

Use the density triangle: D=MxV

Switch for variables, V=M/D

Plug in numbers, 15.8g/7.9g/cm^3=2cm^3

7 0
4 years ago
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