Mercury (II) oxide decomposes to mercury and oxygen. In the chemical equation below, what is the subscript, x, on the oxygen equ
1 answer:
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Answer:
The temperature of the air at this given elevation will be 53.32425°C
Explanation:
We can calculate the final temperature through the combined gas law. Therefore we will need to know 1 ) The initial volume, 2 ) The initial temperature, 3 ) Initial Pressure, 4 ) Final Volume, 5 ) Final Pressure.
Initial Volume = 1.2 L ; Initial Temperature = 25°C = 298.15 K ; Initial pressure = 1.0 atm ; Final Volume = 1.8 L ; Final pressure = 0.73 atm
We have all the information we need. Now let us substitute into the following formula, and solve for the final temperature ( T ),
PV
/ T
= P
V
/ T
,
T = P
V
T
/ P
V
,
T = 0.73 atm
1.8 L
298.15 K / 1 atm
1.2 L = ( 0.73
1.8
298.15 / 1
1.2 ) K = 326.47425 K,
T = 326.47425 K = 53.32425 C