1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
soldi70 [24.7K]
3 years ago
5

A force in the +x-direction with magnitude F(x)=18.0N−(0.530N/m)x is applied to a 8.40 kg box that is sitting on the horizontal,

frictionless surface of a frozen lake. F(x) is the only horizontal force on the box. So, If the box is initially at rest at x=0, what is its speed after it has traveled 16.0 m? Express your answer to three significant figures and include the appropriate units.
Physics
1 answer:
Fynjy0 [20]3 years ago
6 0

Answer:v=7.24 m/s

Explanation:

Given

F(x)=18-0.530 x

mass m=8.40 kg

box is at rest at x=0

Distance traveled=16 m

mv\frac{\mathrm{d} v}{\mathrm{d} x}=F=\left ( 18-0530x\right )dx

\int_{0}^{v}vdv=\int_{0}^{16}\left ( 18-0.530x\right )dx

\frac{mv^2}{2}=\left ( 18x-0530\frac{x^2}{2}\right )_0^{16}

v^2=\frac{288-67.841\times 2}{8.40}

v=7.24 m/s

You might be interested in
What does the equation n =Pout/Pin mean
V125BC [204]
<span>Basically, the variable n is equal to the amount of P out of the system divided by the about of P into the system

</span>
7 0
3 years ago
Read 2 more answers
Where would you find an inclined plane in a fan
ivanzaharov [21]
The blades that spin around in the fan, because they are flat and produce work
8 0
3 years ago
Read 2 more answers
Which law of motion accounts for the following statement?
strojnjashka [21]
I know that its not the second law. I'm almost positive its the first one. Please let me know if I'm wrong. This sentence makes no sense when you put it with the third law. So, the first law is my guess...
3 0
3 years ago
Read 2 more answers
a. When the electric field between the plates is 75% of the dielectric strength and energy density of the stored energy is 2800
Olegator [25]

Answer: The value of the dielectric constant k = 1.8

Explanation:

If C= ε A/d and

Electrostatic energy W = 1/2CV^2

Substitutes C in the first formula into the energy formula.

W = 1/2 ε A/d × V^2

Let us remember that electric field strength E is the ratio of potential V to the distance d. Where V = Ed

Substitute V = Ed into the energy W.

W = 1/2 × ε A/d ×( Ed )^2

W = 1/2 × ε A/d × E^2 × d^2

d will cancel one of the ds

W = 1/2 × ε Ad × E^2

W/Ad = 1/2 × ε × E^2

W/V = 1/2 × ε E^2

Where Ad = volume V

E = dielectric strength

εo = permittivity of free space = 8.84 x 10^-12 F/m

W/V = 2800 J/m^3

Let first calculate the dielectric strength

2800 = 1/2 × 8.84×10^-12 × E^2

5600 = 8.84×10^-12E^2

E^2 = 5600/8.84×10^-12

E = sqrt( 6.3 × 10^14)

E = 25 × 10^7

75% of E = 18.9 × 10^6Jm

The permittivity of the material will be achieved by using the same formula

2800 = 1/2 × ε E^2

2800 = 0.5 × ε × (18.9×10^6)^2

2800 = ε × 1.78 × 10^14

ε = 2800/1.78×10^14

ε = 1.57 × 10^-11

Dielectric constant k = relative permittivity

Relative permittivity is the ratio of the permittivity of the material to the permittivity of the vacuum in a free space. That is

k = 1.57×10^-11/8.84×10^-12

k = 1.776

k = 1.8 approximately

Therefore, the value of the dielectric constant k is 1.8

3 0
2 years ago
An alpha particle has a charge of +2e and a mass of 6.64 x 10-27 kg. It is accelerated from rest through a potential difference
kondor19780726 [428]

Answer:

a) v = 1.075*10^7 m/s

b) FB = 7.57*10^-12 N

c) r = 10.1 cm

Explanation:

(a) To find the speed of the alpha particle you use the following formula for the kinetic energy:

K=qV          (1)

q: charge of the particle = 2e = 2(1.6*10^-19 C) = 3.2*10^-19 C

V: potential difference = 1.2*10^6 V

You replace the values of the parameters in the equation (1):

K=(3.2*10^{-19}C)(1.2*10^6V)=3.84*10^{-13}J

The kinetic energy of the particle is also:

K=\frac{1}{2}mv^2       (2)

m: mass of the particle = 6.64*10^⁻27 kg

You solve the last equation for v:

v=\sqrt{\frac{2K}{m}}=\sqrt{\frac{2(3.84*10^{-13}J)}{6.64*10^{-27}kg}}\\\\v=1.075*10^7\frac{m}{s}

the sped of the alpha particle is 1.075*10^6 m/s

b) The magnetic force on the particle is given by:

|F_B|=qvBsin(\theta)

B: magnitude of the magnetic field = 2.2 T

The direction of the motion of the particle is perpendicular to the direction of the magnetic field. Then sinθ = 1

|F_B|=(3.2*10^{-19}C)(1.075*10^6m/s)(2.2T)=7.57*10^{-12}N

the force exerted by the magnetic field on the particle is 7.57*10^-12 N

c) The particle describes a circumference with a radius given by:

r=\frac{mv}{qB}=\frac{(6.64*10^{-27}kg)(1.075*10^7m/s)}{(3.2*10^{-19}C)(2.2T)}\\\\r=0.101m=10.1cm

the radius of the trajectory of the electron is 10.1 cm

6 0
3 years ago
Other questions:
  • PLEASE HELP!!
    8·2 answers
  • Sinkholes can form when
    8·2 answers
  • mike's car can accelrate from 0 mph to 40 mph in 5 sec. what is the acceleration of his car miles per hour per sec?
    11·1 answer
  • What is in the blank?
    7·1 answer
  • The MSDS for glacial acetic acid says that it is a flammable liquid that can severely burn any human tissue it comes in contact
    13·2 answers
  • What two things are necessary for work to be done on an object?
    5·1 answer
  • True or False? The superposition or overlapping of two waves always results in destructive interference between the different wa
    10·1 answer
  • A _____________ is any visual, audio, audiovisual, or other sensory material used to enhance a verbal message.
    5·1 answer
  • Can anyone help me please​
    7·1 answer
  • Please help me to solve this, I don’t really know what to do.
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!