Answer: a) 456.66 s ; b) 564.3 m
Explanation: The time spend to cover any distance a constant velocity is given by:
v= distance/time so t=distance/v
The slower student time is: t=780m/0.9 m/s= 866.66 s
For the faster students t=780 m/1,9 m/s= 410.52 s
Therefore the time difference is 866.66-410.52= 456.14 s
In order to calculate the distance that faster student should walk
to arrive 5,5 m before that slower student, we consider the follow expressions:
distance =vslower*time1
distance= vfaster*time 2
The time difference is 5.5 m that is equal to 330 s
replacing in the above expression we have
time 1= 627 s
time2 = 297 s
The distance traveled is 564,3 m
Answer:
![\begin{array}{l|l}\text{Speed}\; \mathrm{(m\cdot s^{-1})} & \text{Minimum Height\;(m)}\\\cline{1-2}\\[-1em] 2 & 0.204\\3&0.459\\4 & 0.815\\5 & 1.27 \\6 & 1.83\end{array}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Bl%7Cl%7D%5Ctext%7BSpeed%7D%5C%3B%20%5Cmathrm%7B%28m%5Ccdot%20s%5E%7B-1%7D%29%7D%20%26%20%5Ctext%7BMinimum%20Height%5C%3B%28m%29%7D%5C%5C%5Ccline%7B1-2%7D%5C%5C%5B-1em%5D%202%20%26%200.204%5C%5C3%260.459%5C%5C4%20%26%200.815%5C%5C5%20%26%201.27%20%5C%5C6%20%26%201.83%5Cend%7Barray%7D)
.
Assumptions:
- The object is dropped in a free fall.
- There's no air resistance.
- The downward acceleration due to gravity is
Explanation:
Consider the "SUVAT" equation
,
where
is the final velocity,
is the initial velocity,
is the acceleration of the object, and
is the change in the object's position.
For example, if the bottle needs to achieve a speed of 
by the time it reaches the ground,
since the statement that the bottle is "dropped" implies a free fall.
.
Apply the previous equation to find the minimum height, :
.
Replace the value and apply the formula to find the minimum height required to reach different final speeds.
By wave particle duality.
Wavelength , λ = h / mv
where h = Planck's constant = 6.63 * 10⁻³⁴ Js, m = mass in kg, v = velocity in m/s.
m = 1kg, v = 4.5 m/s
λ = h / mv
λ = (6.63 * 10⁻³⁴) /(1*4.5)
λ ≈ 1.473 * 10⁻³⁴ m
Option D.
Answer:
The two helicopters have the same kinetic energy, but a different GPE, or gravitational potential energy.
Explanation:
Answer:
a = 0.63 m/s²
Explanation:
given,
mass of submarine = 1460-kg
upward buoyant force = 16670 N
downward resistive force = 1150 N
submarine acceleration = ?
assuming g = 10 m/s²
now,
B - (R + mg) = ma
16670 - 1150 - 1460 × 10 = 1460 × a
1460× a = 920
a = 0.63 m/s²
hence, the acceleration of submarine is equal to a = 0.63 m/s²
