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Over [174]
2 years ago
5

1) When you hold your nose and go underwater, you can still hear sounds that are made above the water, in the air, if they are l

oud enough. This is because the _________________ in the air get transferred to the water.
Physics
2 answers:
Deffense [45]2 years ago
6 0

Answer:

Vibrations

Explanation:

That is why when under water it sounds muffled and you cannot hear clearly.

Firdavs [7]2 years ago
5 0

Answer:

Vibrations

Explanation:

Vibrations are transferred through water. That's how dolphins are able to tell where food, family, and objects are

please vote brainliest!!

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Which of the following is the best definition of energy?
Montano1993 [528]
Energy is the capacity to do some type of work
8 0
3 years ago
In the picture of the atom above, what subatomic particle does the letter A represent?
ra1l [238]

Answer:

Electron

Explanation:

In the picture, the letter A is pointing to an electron.

4 0
2 years ago
A 2.5 m -long wire carries a current of 8.0 A and is immersed within a uniform magnetic field B⃗ . When this wire lies along the
leva [86]

Answer:

Explanation:

Let the magnetic field be B = B₁i + B₂j + B₃k

Force = I ( L x B )  , I is current , L is length and B is magnetic field .

In the first case

force = - 2.3 j N

L = 2.5 i

puting the values in the equation above

- 2.3 j = 8 [ 2.5 i x ( B₁i + B₂j + B₃k )]

= - 20 B₃ j + 20 B₂ k

comparing LHS and RHS ,

20B₃ = 2.3

B₃ = .115

B₂ = 0

In the second case

L = 2.5 j

Force = I ( L x B )

2.3i−5.6k = 8 ( 2.5 j x (B₁i + B₂j + B₃k )

=  - 20 B₁ k + 20B₃ i

2.3i−5.6k = - 20 B₁ k + 20B₃ i

B₃ = .115

B₁ = .28

So magnetic field B = .28 i + .115 B₃

Part A

x component of B = .28 T

Part B

y component of B = 0

Part C

z component of B = .115 T .

8 0
3 years ago
Calculate the wavelength (in nm) of the blue light emitted by a mercury lamp with a frequency of 6.88 × 1014 Hz. The speed of li
Nezavi [6.7K]

Answer: 430 nm.

Explanation:

The relation of wavelength and frequency is:

Formula used : \nu=\frac{c}{\lambda}

where,

\nu = frequency =6.88\times 10^{14}Hz

\lambda = wavelength  = ?

c = speed of light = 3.00\times 10^{8}m/s

Now put all the given values in this formula, we get

6.88\times 10^{14}=\frac{3.00\times 10^{8}m/s}{\lambda}

\lambda=\frac{3.00\times 10^{8}m/s}{6.88\times 10^{14}}=0.43\times 10^{-6}m=430m        (1nm=10^{-9}m)

Thus the wavelength (in nm) of the blue light emitted by a mercury lamp is 430 nm.

6 0
3 years ago
Two stationary positive point charges, charge 1 of magnitude 3.90 nC and charge 2 of magnitude 1.80 nC, are separated by a dista
soldi70 [24.7K]

Answer:

v = 7793150 m/s

Explanation:

First, we are going to calculate the electrical potential in the point middle between the two charges

Remember that the electrical potential can be calculated as:

v = \frac{kQ}{r}

                 Where     k = 8.9874 x 10^{9} \frac{Nm^{2} }{C^{2} }

and it is satisfy the superposition principle, thus

v = \frac{8.9874x10^{9}(3.90x10^{-9} ) }{0.23} +  \frac{8.9874x10^{9}(1.80x10^{-9} ) }{0.23}

v = 222.73v

The electrical potential at 10 cm from charge 1 is:

v = \frac{8.9874x10^{9}(3.90x10^{-9} ) }{0.1} +  \frac{8.9874x10^{9}(1.80x10^{-9} ) }{0.36}

v = 395.44 v

Since the work - energy theorem, we have:

q\Delta v = \frac{mv^{2} }{2}

                     where q is the electron's charge and m is the electron's mass

Therefore:

v = \sqrt{\frac{2q\Delta v}{m} }

v = 7793150 m/s

6 0
2 years ago
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