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IRINA_888 [86]
2 years ago
12

BRainliest if correct (if you don't know don't answer.) 2

Physics
2 answers:
klemol [59]2 years ago
6 0
Diagram B .... light shines through at an angle
max2010maxim [7]2 years ago
5 0

Diagram B

Explanation:

because when light passes from a denser to a rarer medium it bends towards the Principal axis due to refraction of light

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A 9 × 1014 Hz laser emits a 8.8 μs pulse, 5.0 mm in diameter, with a beam energy density of 0.8 J/m3. The number of wavelengths
julsineya [31]

To solve this problem we will apply the concepts related to Frequency (Reverse to Period) and the description of the wavelength as a function of the speed of light at the rate of frequency.

Our Laser frequency is given as

f = 9*10^{14}Hz

Therefore the laser wavelength would be

\lambda = \frac{c}{f}

Where,

c = Speed of light

f = Frequency

\lambda = \frac{3*10^8}{ 9*10^{14}}

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Therefore the pulse wavelength would be

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