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3 years ago

BRainliest if correct (if you don't know don't answer.) 2

Physics

2 answers:

klemol [59]3 years ago

6 0

Diagram B .... light shines through at an angle

max2010maxim [7]3 years ago

5 0

Diagram B

Explanation:

because when light passes from a denser to a rarer medium it bends towards the Principal axis due to refraction of light

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What happens to water when it changes to ice?

mamaluj [8]

When water changes to ice, its density decreases and its volume increases.

7 0

3 years ago

A car with a mass of 710 kg is traveling at 37 km/hr. It accelerates to a speed of 120 km/hr in 12.6 seconds. What is the net fo

guajiro [1.7K]

Answer: The net force acting on the car 1,299.3 N.

Explanation:

Mass of the car = 710 kg

Initial velocity of the car of the ,u= 37 km/h= 10.27 m/s $(1km\h=\frac{5}{18} m/s)$

Final velocity of the car,v = 120 km/h = 33.33 m/s

time taken b y car = 12.6 sec

v-u=at

$33.33m/s-10.27m/s=23.06 m/s=a(12.6 sec)$

$a = 1.83 m/s^2$

$Force=mass\times acceleration$

$Force=710 kg\times 1.83 m/s^2$

$Force=1,299.3 N$

The net force acting on the car 1,299.3 N.

8 0

3 years ago

Two loudspeakers, 4.5 m apart and facing each other, play identical sounds of the same frequency. You stand halfway between them

irga5000 [103]

Answer:

A) Frequency of Sound B = 242.85 Hz

B) Frequency at maximum sound intensity = 485.71 Hz

Explanation:

From intensity and path difference equations of sound waves;

the path difference for maximum intensity is x = nλ

Now, for minimum intensity, the path difference(x) is given as;

x = (2n - 1)(λ/2)

Since he has moved 0.35m,the total Path difference = (0.35) + (0.35) = 0.7 m

As n = 1,

0.7 = =(2(1) - 1)(λ/2)

So, (λ/2) = 0.7

And thus λ = 0.7 x 2 = 1.4m

From wavelength equation, we know that; λ = v/f and f = v/λ

Where v is velocity of sound

Thus ; frequency(min) = 340/1.4= 242.85 Hz

B) Now for max the path difference;

From earlier said, x = nλ

So at n=1 and λ = 0.7

x = 1 x 0.7 = 0.7

So following same equation for frequency, fmax = 340/0.7 = 485.71 Hz

3 0

3 years ago

Two blocks are suspended from opposite ends of a light rope that passes over a light, frictionless pulley. One block has mass m1

rewona [7]

Answer:

a) m₁ = 1.41 kg , b) m₂ = 2.65 kg

Explanation:

For this exercise we will use Newton's second law

Block 1

T - W₁ = m₁ a

Block 2

W₂ - T = m₂ a

We have selected the positive block 1 rising and block two lowering, as the pulley has no friction does not affect the movement

Let's use kinematics to look for acceleration

y = v₀ t + ½ a t²

As part of the rest the initial speed is zero

a = 2 y / t²

a = 2 6.00 / 2²

a = 3 m / s²

Let's replace in the equation of block 1

a) T = m₁ g + m₁ a

m₁ = T / (g + a)

m₁ = 18.0 / (9.8 + 3)

m₁ = 1.41 kg

b) we substitute in the equation of block 2

W₂ - T = m₂ a

m₂ g - m₂ a = T

m₂ = T / (g-a)

m₂ = 18.0 / (9.8 -3)

m₂ = 2.65 kg

4 0

3 years ago

What is the velocity of an object that has been in free fall for 2.5 s?

zvonat [6]

Answer: D. 25 m/s Downward

Explanation:

V = (g)(t)

V = (9.8 m/s²)(2.5)

V = 24.5 m/s

8 0

3 years ago