1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
IRINA_888 [86]
2 years ago
12

BRainliest if correct (if you don't know don't answer.) 2

Physics
2 answers:
klemol [59]2 years ago
6 0
Diagram B .... light shines through at an angle
max2010maxim [7]2 years ago
5 0

Diagram B

Explanation:

because when light passes from a denser to a rarer medium it bends towards the Principal axis due to refraction of light

You might be interested in
Use Kepler’s laws and the period of the Moon (27.4 d) to determine the period of an artificial satellite orbiting very near the
miv72 [106K]

As according to Kepler 's law

T =(4π²r³/ Gm)^1/2

here r= distance  from earth center to satellite = 6400km = 6400000m

G = earth's gravitational constant= 6.67×10^-11

m = mass of earth= 5.98 ×10^24

so T =[ { 4× (3.1416)²×(6400000)³}/ {(6.67×10^-11)×( 5.98 ×10^24)} ]^1/2

T= 5133 sec


7 0
2 years ago
Read 2 more answers
To water the yard you use a hose with a diameter of 3.2 cm. Water flows from the hose with a speed of 1.1 m/s. If you partially
cupoosta [38]

Answer:

The speed of water flow inside the pipe at point - 2 = 34.67 m / sec

Explanation:

Given data

Diameter at point - 1 = 3.2 cm

Velocity at point - 1 = 1.1 m / sec = 110 cm / sec

Diameter at point - 2 = 0.57 cm

Velocity at point - 2 = ??

We know that from the continuity equation the rate of flow is constant inside  a pipe between two points.

Thus

⇒ A_{1} × V_{1} = A_{2} × V_{2}

⇒  \frac{\pi }{4} × d_{1} ^{2} × V_{1} =

⇒  d_{1} ^{2} × V_{1} =  d_{2} ^{2}  × V_{2}

⇒  (3.2)^{2} × 110 = (0.57)^{2} × V_{2}

⇒ V_{2} = 3467 cm / sec

⇒ V_{2} = 34.67 m / sec  

Thus the speed of water flow inside the pipe at point - 2 = 34.67 m / sec

3 0
3 years ago
What’s the net force of an object being throwing into the air
timurjin [86]

Answer: forces acting on an object being thrown into the air is gravity and possibly air resistance

Explanation:

4 0
2 years ago
You are driving at the speed of 33.4 m/s (74.7296 mph) when suddenly the car in front of you (previously traveling at the same s
romanna [79]

Answer:

Part a)

a = - 8.45 m/s/s

Part b)

d = 66 m

Part c)

d = 14.16 m

Explanation:

Part a)

when car apply brakes then the friction force on the car in front of us is given as

F_f = \mu mg

here we need to find deceleration due to friction

a = \frac{F_f}{m}

a = -\mu g

a = -8.45 m/s^2

Part b)

Braking distance of the car is the distance that it move till it stops

so we will have

v_f^2 - v_i^2 = 2ad

0 - 33.4^2 = 2(-8.45)d

d = 66 m

Part c)

Since we know that average reaction time for human is 0.424 s

now we know that during reaction time our car will travel at uniform speed

so we will have

d = vt

d = (33.4) (0.424)

d = 14.16 m

4 0
2 years ago
A horizontal force, F1 = 65 N, and a force, F2 = 12.4 N acting at an angle of θ to the horizontal, are applied to a block of mas
Nezavi [6.7K]

Answer:

(a) FN = 24.18 N

(b) a = 22.87 m/s²

Explanation:

Newton's second law of the  block:

∑F = m*a Formula (1)

∑F : algebraic sum of the forces in Newton (N)

m : mass in kilograms (kg)

a : acceleration in meters over second square (m/s²)

Forces acting on the box

We define the x-axis in the direction parallel to the movement of the block on the surface   and the y-axis in the direction perpendicular to it.

F₁ : Horizontal force

F₂ : acting at an angle of θ to the horizontal,

W: Weight of the block  : In vertical direction

FN : Normal force : perpendicular to the direction the surface

fk : Friction force: parallel to the direction to the surface

Known data

m =3.1 kg : mass of the  block

F₁ = 65 N,  horizontal force

F₂ = 12.4 N acting at an angle of θ to the horizontal

θ = 30° angle θ of F₂ with respect to the horizontal

μk = 0.2 : coefficient of kinetic friction between the block and the surface

g = 9.8 m/s² : acceleration due to gravity

Calculated of the weight  of the block

W= m*g  = (3.1 kg)*(9.8 m/s²) = 30.38 N

x-y F₂ components

F₂x = F₂cos θ= (12.4)*cos(30)° = 10.74 N

F₂y = F₂sin θ= (12.4)*sin(30)° = 6.2 N

a)Calculated of the Normal force  (FN)

We apply the formula (1)

∑Fy = m*ay    ay = 0

FN+6.2-30.38 = 0

FN = -6.2+30.38

FN = 24.18 N

Calculated of the Friction force:

fk=μk*N=  0.2* 24.18 N = 4.836 N

b) We apply the formula (1) to calculated acceleration of the block:

∑Fx = m*ax ,  ax= a  : acceleration of the block

F₁ + F₂x -fk = ( m)*a

65 N + 10.74 -4.836 = ( 3.1)*a

70.904 = ( 3.1)*a

a = (70.904 ) / ( 3.1)

a = 22.87 m/s²

4 0
2 years ago
Other questions:
  • Oil having a density of 930 kg/m^3 floats on
    10·1 answer
  • If there were no air resistance, how long would it take a free-falling skydiver to fall from a plane at 3500 m to an altitude of
    15·1 answer
  • How does the yarn in the sweater differ from the wool on the sheep
    11·2 answers
  • A ray in plastic has a critical angle of 44.4 deg when trying to enter air. What is the index of refraction for the plastic?
    7·1 answer
  • Question 8 of 10
    13·1 answer
  • There is less difference between the speed of light in glass and the speed of light in water than there is between the speed of
    5·1 answer
  • A student locates a double-slit assembly 1.40 m from a reflective screen. The slits are separated by 0.0572 mm. (a) Suppose the
    15·1 answer
  • A rifle of mass M is initially at rest. A bullet of mass m is fired from the rifle with a velocity of v relative to the ground.
    6·1 answer
  • Which statement describes how a machine can help make work easier? It can put out more force than the input force by decreasing
    14·2 answers
  • On what factors do pressure depend ​
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!