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Varvara68 [4.7K]

3 years ago

3

Water would be considered a _______. a. potential renewable resource b. potential nonrenewable resource c. actual renewable reso

urce d. actual nonrenewable resource Please select the best answer from the choices provided A B C D

1 answer:

Sliva [168]3 years ago

7 0

Answer:

c

Explanation:

renewable resources

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At t = 0, one toy car is set rolling on a straight track with initial position 13.5 cm, initial velocity -4.2 cm/s, and constant

Blizzard [7]

(a) We must first look at the formulas of the velocities of each toy car. v1 =
-4.2 + 2.60t. v2 = 5.20. When the two cars have equal speed, then
v1 = v2
-4.2 + 2.60t = 5.20
2.60t = 9.40
t = 3.62 s

(b) Their speed would then be 5.20 m/s. The toy car does not change speed since it doest not have any acceleration.
(c) The two cars will pass each other when their positions are equal.
x1 = 13.5 - 4.2t + 0.5*2.60t^2
x2 = 8.5 + 5.20t
x1 = x2
13.5 - 4.2t + 1.30t^2 = 8.5 + 5.20t
1.30t^2 - 9.40t + 5.0 = 0
t = 6.65s or t = 0.58 s

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I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

3 0

3 years ago

What form of braking is used to bring a vehicle to a smooth stop by applying smooth,steady pressure to the brake

Sav [38]

Answer:

Controlled braking

Explanation:

CONTROLLED BRAKING occur in a situation where a person or an individual driving a vehicle releases the brake and slowly apply smooth as well as firmly pressure on the brake without the wheels been locked which is why CONTROLLED BRAKING are often used for emergency stops by drivers reason been that it helps to reduce speed when driving as fast as possible while the driver maintain the steering control of the vehicle.

Therefore the form of braking which is used to bring a vehicle to a smooth stop by applying smooth,steady pressure to the brake is called CONTROLLED BRAKING.

7 0

3 years ago

A 296-kg motorcycle is accelerating up along a ramp that is inclined 26.2° above the horizontal. The propulsion force pushing th

Alexeev081 [22]

Answer:

The magnitude of the motorcycle's acceleration is 5.20 m/s².

Explanation:

Given that,

Mass of motorcycle = 296 kg

Angle = 26.2°

Force on motorcycle= 3106 N

Force = 286 N

We need to calculate the magnitude of the motorcycle's acceleration

The net force acting on the motorcycle

Using newton's second law

$ma=F_{p}-F_{air}-F_{g}$

$ma=F_{p}-F_{air}-mg\sin\theta$

Put the value into the formula

$296a=3106-286-296\times9.8\times\sin26.2$

$a=\dfrac{3106-286-296\times9.8\times\sin26.2}{296}$

$a=5.20\ m/s^2$

Hence, The magnitude of the motorcycle's acceleration is 5.20 m/s².

5 0

3 years ago

A 10-gram aluminum cube absorbs 677 joules when its temperature is increased from 50°c to 125°

kotegsom [21]

Answer : The specific heat of aluminum is, $0.90J/g^oC$

Solution : Given,

Heat absorbs = 677 J

Mass of the substance = 10 g

Final temperature = $125^oC$

Initial temperature = $50^oC$

Formula used :

$Q= m\times c\times \Delta T$

or,

$Q= m\times c\times (T_{final}-T_{initial})$

Q = heat absorbs

m = mass of the substance

c = heat capacity of aluminium

$T_{final}$ = final temperature

$T_{initial}$ = initial temperature

Now put all the given values in the above formula, we get the specific heat of aluminium.

$677g= (10g)\times c\times (125-50)^oC$

$c=0.9026J/g^oC=0.90J/g^oC$

Therefore, the specific heat of aluminum is, $0.90J/g^oC$

7 0

3 years ago

Read 2 more answers

Party hearing. As the number of people at a party increases, you must raise your voice for a listener to hear you against the ba

dusya [7]

Answer:

$\frac{r_i}{1.77} m$

Explanation:

Given that

At starting separated = 1.20m

And the increase in background noise by Δβ = 5 dB, due to which the level of sound also rises

Based on the above information, the separation rf that is needed is shown below:

As we know that

$I_f = I_o \times 10^{\frac{\beta}{10} }\\\\I_f = I_i \times 10^{0.5}\\\\I_f = 3.16 \times I_i\\\\I \alpha \frac{1}{r^2} \\\\\frac{r_i^2}{r_f^2} = 3.16\\\\r_f = \frac{\sqrt{r_i^2}}{{\sqrt3.16}} \\\\= \frac{r_i}{1.77} m$

Hence, the separation r_f i.e. required is $\frac{r_i}{1.77} m$

We simply applied the above equation so that the correct separation could come

6 0

3 years ago