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3 years ago

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A fission reaction possible is that certain atoms are

1 answer:

Elden [556K]3 years ago

8 0

The process of splitting a nucleus<span> is called </span>nuclear fission<span>. Uranium or plutonium isotopes are normally used as the fuel in </span>nuclear<span> reactors because their </span>nuclei<span> are relatively large and easy to split. For </span>fission<span> to </span>happen<span>, the uranium-235 or plutonium-239 </span>nucleus<span> must first absorb a neutron.</span>

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You are sitting on a merry-go-round at a distance of 2m from its center. It spins 15 times in 3 min. What distance do you move a

soldier1979 [14.2K]

Answer:

A) 12.57 m

B) 5 RPM

C) 3.142 m/s

Explanation:

A) Distance covered in 1 Revolution:

The formula that gives the relationship between the arc length or distance covered during circular motion to the angle subtended or the revolutions, is given as follows:

s = rθ

where,

s = distance covered = ?

r = radius of circle = 2 m

θ = Angle = 2π radians (For 1 complete Revolution)

Therefore,

s = (2 m)(2π radians)

<u>s = 12.57 m</u>

B) Angular Speed:

The formula for angular speed is given as:

ω = θ/t

where,

ω = angular speed = ?

θ = angular distance covered = 15 revolutions

t = time taken = 3 min

Therefore,

ω = 15 rev/3 min

<u>ω = 5 RPM</u>

C) Linear Speed:

The formula that gives the the linear speed of an object moving in a circular path is given as:

v = rω

where,

v = linear speed = ?

r = radius = 2 m

ω = Angular Speed in rad/s = (15 rev/min)(2π rad/1 rev)(1 min/60 s) = 1.571 rad/s

Therefore,

v = (2 m)(1.571 rad/s)

<u>v = 3.142 m/s</u>

8 0

3 years ago

When humans started launching rockets into outer space, they needed to make certain the rockets had enough power to escape Earth

GaryK [48]

Tha answer has to be a

5 0

3 years ago

A 23.5 g piece of aluminum metal is initially at 100.0°C. It is dropped into a coffee cup-calorimeter containing 130.0 g of wate

vivado [14]

Answer: The molar heat capacity of aluminum is $25.3J/mol^0C$

Explanation:

$heat_{absorbed}=heat_{released}$

As we know that,

$Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})$

$m_1\times c_1\times (T_{final}-T_1)=-[m_2\times c_2\times (T_{final}-T_2)]$ .................(1)

where,

q = heat absorbed or released

$m_1$ = mass of water = 130.0 g

$m_2$ = mass of aluminiunm = 23.5 g

$T_{final}$ = final temperature = $26.0^oC=(273+26)K=299K$

$T_1$ = temperature of water = $23^oC=(273+23)K=296K$

$T_2$ = temperature of aluminium = $100^oC=273+100=373K$

$c_1$ = specific heat of water= $4.184J/g^0C$

$c_2$ = specific heat of aluminium= ?

Now put all the given values in equation (1), we get

$130.0\times 4.184\times (299-296)=-[23.5\times c_2\times (299-373)]$

$c_2=0.938J/g^0C$

Molar mass of Aluminium = 27 g/mol

Thus molar heat capacity = $0.938J/g^0C\times 27g/mol=25.3J/mol^0C$

5 0

3 years ago

The resistance of the body varies from approximately 500 kΩ (when it is very dry) to about 1.00kΩ (when it is wet). The maximum

Nady [450]

Answer:

you absolute buffoon Use Ohms' Law: V = RI

V = (1x10^3)(5x10^-3) = 5 volts

Yes, this is in the range of normal household voltages.

Explanation:

4 0

3 years ago

Match each term to its definition.

den301095 [7]

Answer: first one is electrochemical
Second one is combustion
Third one is photosynthesis
Fourth one is respiration

8 0

3 years ago

Read 2 more answers