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2 years ago

How much pressure is created when you apply a

Physics

1 answer:

Alekssandra [29.7K]2 years ago

5 0

Pressure
= Force/Area

Area = π(d^2)/4
= π(0.4^2)/4
=0.126 m2
Pressure
= 50/0.126
= 396.825 Pa

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A 0.145 kg baseball is thrown with a velocity of 40 m/s. What is the baseball's momentum?

Rom4ik [11]

The momentum, p, is the product of the mass and the velocity:
p = m*v = 0.145 kg * 40 m/s = 5.8 kg*m/s

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3 years ago

If the y component of a vector is 36, and the angle between the vector and the x-axis is 27, what is the magnitude of the vector

statuscvo [17]

Answer:

79.29

Explanation:

Given that,

The y component of a vector, y = 36

The angle between the vector and the x-axis is 27.

We need to find the magnitude of a vector.

Let a and b are x and y component of a vector m. There resultant is R. So,

$R=\sqrt{a^2+b^2}$

Where

$a=c\cos\theta\ \text{and}\ b=c\sin\theta$

We have, b = 36 and θ = 27°

So,

$36=R\sin\theta\\\\R=\dfrac{36}{\sin\theta}\\\\R=\dfrac{36}{\sin(27)}\\R=79.29$

So, the magnitude of the vector is 79.29

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3 years ago

A centrifuge is used to test space pilots. The centrifuge spins with a centripetal acceleration of 3.04g. If the length of the a

uranmaximum [27]

Answer:

$approx.= 25\frac{m}{s}$

Explanation:

Centripetal acceleration (a) is defined as the square of an object's velocity (V^2) divided by the distance of the object from it's point/axis of revolution (r). So:

$a=\frac{V^{2} }{r}$

which allows us to solve for the velocity:

$V=\sqrt{ar}\\ Since: a=3.04g=(3.04)(9.81),r=21;\\V=\sqrt{(3.04)(9.81)(21)} =25.02...$

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4 years ago

What is the difference between a molecule and a compuond?

frosja888 [35]

All compounds are molecules but not all molecules are compounds.
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3 years ago

A sledder is at rest atop a 5.0-m high hill. She’s texting and doesn’t realize her sled starting to slip, moving her to the bott

djyliett [7]

Answer: V = 7.75m/s

Explanation:

In this problem, we will consider conservation of energy where gravitational potential energy is converted into kinetic energy.

Please find the attached file for the solution.

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3 years ago