Answer:
28.16 g/mol
Explanation:
From Graham's law;
Let the rate of diffusion of gas X be 1.25
Let the rate of diffusion of CO2 be 1
Molecular mass of gas X= M
Molecular mass of CO2 = 44g/mol
1.25/1=√44/M
(1.25/1)^2 = 44/M
1.5625 = 44/M
M= 44/1.5625
M= 28.16 g/mol
Answer:
Quantity A is weight and Quantity B is mass
Explanation: weight has same unit as force. Mass is the quantity of matter present in a body or object
Answer:
ΔH₁₂ = -867.2 Kj
Explanation:
Find enthalpy for 3H₂ + O₃ => 3H₂O given ...
2H₂ + O₂ => 2H₂O ΔH₁ = -483.6 Kj
3O₂ => 2O₃ ΔH₂ = + 284.6 Kj
_____________________________
3(2H₂ + O₂ => 2H₂O) => 6H₂ + 3O₂ => 6H₂O (multiply by 3 to cancel O₂)
6H₂ + 3O₂ => 6H₂O ΔH₁ = 3(-483.6 Kj) = -1450.6Kj
2O₃ => 3O₂ ΔH₂ = -284.6Kj (reverse rxn to cancel O₂)
_______________________________
6H₂ + 2O₃ => 6H₂O ΔH₁₂ = -1735.2 Kj (Net Reaction - not reduced)
________________________________
divide by 2 => target equation (Net Reaction - reduced)
3H₂ + O₃ => 3H₂O ΔH₁₂ = (-1735.2/2) Kj = -867.2 Kj
Answer:
sugar in melk
Explanation:
cow eat sugar then make sugar :)
