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2 years ago

a solution of HCI contains 36 percent HCI,by mass and calculate the mole fraction of HCI in the solution?

Chemistry

1 answer:

denis-greek [22]2 years ago

4 0

Explanation:

You have a solution that contains 36 g HCl dissolved in 64 g water

Molar mass HCl = 36.45 g/mol

Mol HCl in 36 g = 36 g / 36.45 g/mol = 0.9876 mol

Molar mass H2O = 18 g/mol

Mol H2O in 64 g = 64 g / 18 g/mol = 3.5556 mol

Total mol = 0.9875 + 3.5556 = 4.5431 mol

Mol fraction HCl = 0.9876 mol / 4.5431 mol = 0.2174

Mol fraction H2O = 3.5556 / 4.5431 = 0.7826

The answer should have 2 significant digits:

Mol fraction HCl = 0.22

Mol fraction H2O = 0.78

Mol fraction has no units.

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What is the percent composition of hydrogen if a sample is found to contain 7 grams of hydrogen, 32 grams of nitrogen, and 7 gra

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<u>Answer:</u> The percent composition of hydrogen in the sample is 15.22 %

<u>Explanation:</u>

We are given:

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$\%\text{ composition of hydrogen}=\frac{\text{Mass of hydrogen}}{\text{Mass of sample}}\times 100$

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6 0

3 years ago

Pls help me with this

Zina [86]

Answer:

$[I_2]=[Br]=0.31M$

Explanation:

Hello there!

In this case, according to the given information, it is possible for us to set up the following chemical equation at equilibrium:

$I_2+Br_2\rightleftharpoons 2IBr$

Now, we can set up the equilibrium expression in terms of x (reaction extent) whereas the initial concentration of both iodine and bromine is 0.5mol/0.250L=2.0M:

$K=\frac{[IBr]^2}{[I_2][Br_2]} \\\\1.2x10^2=\frac{(2x)^2}{(2.0-x)^2}$

Thus, we solve for x as show below:

$\sqrt{1.2x10^2} =\sqrt{\frac{(2x)^2}{(2.0-x)^2}} \\\\10.95=\frac{2x}{2.0-x}\\\\21.91-10.95x=2x\\\\21.91=12.95x\\\\x=\frac{21.91}{12.95} \\\\x=1.69M$

Therefore, the concentrations of both bromine and iodine are:

$[I_2]=[Br]=2.0M-1.69M=0.31M$

Regards!

8 0

3 years ago

The nearest whole number of 99.59

Anna [14]

It is 100 because a 5 and up means you round up. also the 9 makes it a 6 rounded up

7 0

3 years ago

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a solution of HCI contains 36 percent HCI,by mass and calculate the mole fraction of HCI in the solution?​

a solution of HCI contains 36 percent HCI,by mass and calculate the mole fraction of HCI in the solution?