Answer:

Step-by-step explanation:
The formula for the length of a vector/line in your case.
![L = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2} = \sqrt{[4 - (-1)]^2 + [2 -(-3)]^2} = \sqrt{5^2 + 5^2} = \sqrt{50} = 5\sqrt{2}](https://tex.z-dn.net/?f=L%20%3D%20%5Csqrt%7B%28x_2-x_1%29%5E2%20%2B%20%28y_2-y_1%29%5E2%7D%20%3D%20%5Csqrt%7B%5B4%20-%20%28-1%29%5D%5E2%20%2B%20%5B2%20-%28-3%29%5D%5E2%7D%20%3D%20%5Csqrt%7B5%5E2%20%2B%205%5E2%7D%20%3D%20%5Csqrt%7B50%7D%20%3D%205%5Csqrt%7B2%7D)
Not sure about the first one,
The second one is 1/9.
Answer:
The number of pies does the baker have left is 15.
Step-by-step explanation:
Given : A baker made 20 pies. A Boy Scout troop buys one–fourth of his pies, a preschool teacher buys one–third of his pies, and a caterer buys one–sixth of his pies.
To find : How many pies does the baker have left?
Solution :
Let x be the number of pies does the baker have left.
According to question,
Number of pies buys,
One-fourth =
One-third =
One-sixth =
i.e. 






The number of pies does the baker have left is 15.
Im not sure but it could be 1/14
There’s technically two answers, you could put Angles 3 and 6, or Angles 7 and 2