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butalik [34]
3 years ago
8

Which of the following would not increase the rate of most reactions? A. Removing an inhibitor B. Lowering the concentration of

the reactants C. Adding a catalyst D. Increasing the temperature
Chemistry
2 answers:
ioda3 years ago
8 0
I think it'd be B.. :) 
Ne4ueva [31]3 years ago
7 0

A few factors influence the rate of reaction, including :

<em>Temperature</em>. Most reactions increase in rate as temperature increases; most reactions slow down as temperature decreases.

<em>Concentrations of the reactant</em>. Raising the concentration of a substance will increase the speed of the reaction; lowering the concentration of a substance will decrease the speed of the reaction. The limiting reactant is the reactant that is completely used up in a reaction. When this is completely used up, the reaction will stop.

<em>Catalysts</em>. These are substances that speed up the rate of the reaction by lowering the activation energy. If a catalyst is added, the rate of reactions will increase. If a catalyst is removed, the rate of reactions will decrease. Enzymes are biological catalysts used in living things to speed up internal reactions.

<em>Inhibitors</em>. These are substances that slow down the rate of a reaction. If an inhibitor is added to a reaction, its rate will decrease. If an inhibitor is removed from a reaction, its rate will increase.

Thus, the right answer is B. Lowering the concentration of the reactants

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When equal molar amounts of the following sets of compounds are mixed in water, which will not form a buffer solution?
krok68 [10]

Nitric acid is a strong acid while the nitrate ion is a very weak base. Nitric acid is able to consume hydroxide ions. However, the nitrate ions present are unable to consume hydronium ions. As a result, the set of compounds does not form a buffer solution.

<h3></h3><h3>What Is Molar Mass?</h3>

A mole is the number of entities present in a substance, such as atoms, molecules, or ions. A mole of any substance is defined as 6.0221023 molecules. Just as we use a standard value to quantify diverse things, such as 1 dozen = 12 items, we utilise the mole to quantitatively calculate the size of the tiniest creatures.

The number of atoms in 12g (0.012 kg) of 12C isotope is equal to the number of particles in 1 mole of the substance. One of the most crucial facts to remember is that the mole of a material always includes the same number of entities regardless of the substance.

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7 0
2 years ago
Differentiate photosynthesis and cellular respiration
scZoUnD [109]

Answer:

Photosynthesis converts carbon dioxide and water into oxygen and glucose. Glucose is used as food by the plant and oxygen is a by-product. Cellular respiration converts oxygen and glucose into water and carbon dioxide. Water and carbon dioxide are by- products and ATP is energy that is transformed from the process.

Explanation:

3 0
3 years ago
Read 2 more answers
How much heat is required to change 25.0 g of water from solid to liquid at 0 oC? Water: ΔHfus = 334 J/g; ΔHvap= 2260J/g
xxMikexx [17]

Answer:

The heat required to change 25.0 g of water from solid ice to liquid water at 0°C  is 8350 J

Explanation:

The parameters given are

The temperature of the solid water = 0°C

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The heat of vaporization, = 2260 J/g

Mass of the solid water = 25.0 g

We note that the heat required to change a solid to a liquid is the heat of fusion, from which we have the formula for heat fusion is given as follows;

ΔH =  m ×

Therefore, we have;

ΔH =  25 g × 334 J/g = 8350 J

Which gives the heat required to change 25.0 g of water from solid ice to liquid water at 0°C  as 8350 J.

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Explain the problem surrounding the ammonia-making process in terms of chemical equilibrium.
bazaltina [42]

Answer is: at lower temperatures the reaction rate would decrease.

The lower is the temperature, the slower the reaction becomes.

The Haber process is procedure for the production of ammonia, in this process atmospheric nitrogen (N₂) is converted to ammonia (NH₃):

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Because this is exothermic reaction (enthalpy is less than zero), at lower temperatures, the equilibrium is in favor of ammonia, but the reaction doesn't proceed at a detectable rate.

5 0
3 years ago
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