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aleksklad [387]
3 years ago
9

The Brownian Motion prevents colloid particles from settling out of a solution. Please select the best answer from the choices p

rovided T F
Chemistry
1 answer:
KonstantinChe [14]3 years ago
7 0
The correct  answer would be true
You might be interested in
4. A 1.802 gram sample of unknown compound contains 0.721 grams of carbon, 0.121 grams of hydrogen and 0.960 grams of oxygen. Th
AysviL [449]

Answer:

Empirical formula is CH2O

The molecular formula is C6H12O6

Explanation: Please see attachment for explanation

7 0
3 years ago
Acetic acid is a weak acid with a pKa of 4.76. What is the concentration of acetic acid in a buffer solution of 0.2M at pH 4.9.
masya89 [10]

Answer:

0.084 M

Explanation:

Using the Henderson-Hasselbalch equation for a buffer ( a buffer is solution contain a weak acid and it conjugate base; the solution resist change in pH)

pH = pKa + log ( base/acid)

4.9 - 4.76 =log ( base / acid)

10^0.14 =  ( base / acid)

1.38 = (base / acid)

since there is 0.2 M in the buffer solution

the concentration of acid =  \frac{1}{(1+1.38)} × 0.2 = 0.084 M

6 0
3 years ago
A solution is 40.00% by volume benzene (C6H6) in carbon tetrachloride at 20°C. The vapor pressure of pure benzene at this temper
finlep [7]

Answer:

The total vapor pressure is 84.29 mmHg

Explanation:

Step 1:  Data given

Solution = 40.00 (v/v) % benzene in CCl4

Temperature = 20.00 °C

The vapor pressure of pure benzene at 20.00 °C = 74.61 mmHg

Density of benzene is 0.87865 g/cm3

The vapor pressure of pure carbon tetrachloride is 91.32 mmHg

We suppose the total volume = 100 mL

Step 2: Calculate volume benzene and CCl4

40 % benzene = 40 mL

60 % mL CCl4 = 60 mL

Step 3: Calculate mass benzene

Mass = density * volume

Mass of benzene = 40.00 mL *  0.87865 g/mL = 35.146 g

Step 4: Calculate moles of benzene

Moles = mass / molar mass

Number of moles of benzene  = 35.146 grams / 78 g/mol  = 0.45059 mol

Step 5: Calculate mass of CCl4

Mass of CCl4 = 60 mL * 1.5940 g/mL = 95.64 g

Step 6: Calculate moles CCl4

Number of moles of CCl4 = 95.64 grams / 154g/mol = 0.62104 mol

Step 7: Calculate total number of moles

Total number of moles = moles benzene + moles CCl4

0.45059 moles + 0.62104 moles = 1.07163 mol

Step 8: Calculate mole fraction benzene and CCl4

Mole fraction = moles benzene / total moles

Mole fraction of benzene = 0.45059 / 1.07163 = 0.4205

Mole fraction of CCl4 = 0.62104 / 1.07163 = 0.5795

Step 9: Calculate partial pressure

Partial pressure of benzene = 0.4205 * 74.61 = 31.37 mmHg

Partial pressure of CCl4      = 0.5795 * 91.32 = 52.92 mmHg

Total vapor pressure = 31.37 + 52.92 = 84.29 mmHg

The total vapor pressure is 84.29 mmHg

7 0
3 years ago
State which separation method you would use to separate potassium iodine solution​
navik [9.2K]
Could be separated by distillation.
3 0
2 years ago
What is one example of a molecule that is not a compound?
Marrrta [24]
Br2 or O2 or N2 or H2 or F2 or I2 etc.
4 0
3 years ago
Read 2 more answers
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