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olganol [36]
2 years ago
15

If the reaction described by this chemical equation started with 5.77 grams of PbO2 and resulted in 0.331 grams of O2, what is t

he percent yield of O2
Chemistry
1 answer:
____ [38]2 years ago
6 0

Answer:

42.9%

Explanation:

Step 1: Write the balanced decomposition reaction

PbO₂ ⇒ Pb + O₂

Step 2: Calculate the theoretical yield of O₂ from 5.77 g of PbO₂

According to the balanced equation, the mass ratio of PbO₂ to O₂ is 239.2:32.00.

5.77 g PbO₂ × 32.00 g O₂/239.2 g PbO₂ = 0.772 g O₂

Step 3: Calculate the percent yield of O₂

The real yield of O₂ is 0.331 g. The percent yield of O₂ is:

%yield = real yield / theoretical yield × 100%

%yield = 0.331 g / 0.772 g × 100% = 42.9%

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Solve fasttt<br><br> C7H17+O2=CO2+H2O<br><br> Balancing Equations
sertanlavr [38]

Answer:

The answer to your question is

                                        4C₇H₁₇  + 45 O₂    ⇒   28 CO₂   +  34H₂O  

Explanation:

Write the equation

                                        C₇H₁₇  +    O₂    ⇒    CO₂   +    H₂O  

Process

1.- Check if the equation is balanced

                                 Reactants            Element              Products

                                        7                          C                           1

                                       17                          H                          2

                                        2                          O                          3

As the number of reactants and products is different, we conclude that the reaction is unbalanced.

2.- Write a coefficient "7" to CO₂   and a coefficient of 17/2 to H₂O

                                      C₇H₁₇  +    O₂    ⇒   7CO₂   +  \frac{17}{2}H₂O  

                                 Reactants            Element              Products

                                        7                          C                           7

                                       17                          H                          17

                                        2                          O                          51/2

3.- Write a coefficient of 45/2 to the O₂, and multiply all the equation by 2.

                         4C₇H₁₇  + 45 O₂    ⇒   28 CO₂   +  34H₂O  

                  Reactants            Element              Products

                        28                          C                        28

                        68                          H                        68

                        90                          O                        90

5 0
3 years ago
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klemol [59]
The first one would be it
6 0
3 years ago
What is the mass of an atom with seven protons, seven neutrons, and eight electrons?
belka [17]

Answer:

14

Explanation:

mass number = protons + neutrons

6 0
3 years ago
What is the chemical formula for aluminum selenide ?​
yulyashka [42]

Al2Se3 is your chemical formula

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7 0
3 years ago
Read 2 more answers
_Fe2O3 + 2CO —&gt; _Fe + _CO2
soldi70 [24.7K]
<h3>Answer:</h3>

Fe₂O₃(s) + 3CO(g) → 2Fe(s) + 3CO₂(g)

<h3>Explanation:</h3>

Concept tested: Balancing of chemical equations

  • A chemical equation is balanced by putting appropriate coefficients on the products and reactants of the equation.
  • Balancing chemical equations ensures that chemical equations obey law of conservation of mass.
  • In this case; to balance the above equation we put the coefficients, 1, 3, 2, and 3 on the reactants and products.
  • Therefore; the balanced chemical equation for the reaction is;

      Fe₂O₃(s) + 3CO(g) → 2Fe(s) + 3CO₂(g)

8 0
3 years ago
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