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olganol [36]
2 years ago
15

If the reaction described by this chemical equation started with 5.77 grams of PbO2 and resulted in 0.331 grams of O2, what is t

he percent yield of O2
Chemistry
1 answer:
____ [38]2 years ago
6 0

Answer:

42.9%

Explanation:

Step 1: Write the balanced decomposition reaction

PbO₂ ⇒ Pb + O₂

Step 2: Calculate the theoretical yield of O₂ from 5.77 g of PbO₂

According to the balanced equation, the mass ratio of PbO₂ to O₂ is 239.2:32.00.

5.77 g PbO₂ × 32.00 g O₂/239.2 g PbO₂ = 0.772 g O₂

Step 3: Calculate the percent yield of O₂

The real yield of O₂ is 0.331 g. The percent yield of O₂ is:

%yield = real yield / theoretical yield × 100%

%yield = 0.331 g / 0.772 g × 100% = 42.9%

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A wave has 9.2 x 10-22 ) of energy. What is its wavelength?
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Answer:

\lambda=2.2x10^{-4}m

Explanation:

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In this case, since the relationship between energy and wavelength is defined via the speed of light and the Planck's constant as shown below:

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Since c stands for the speed of light and h for the so-called Planck's constant, we can compute the wavelength as follows:

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The volume of a pond being studied for the effects of acid rain is 35 kiloliters (kL). There are 1,000 liters (L) in 1 kL and 1
Lerok [7]

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4 0
3 years ago
If 10.0 mL of a .600 M of HNO3 reacts with 31.0 mL of .700M Ba(OH)2 solution, what is the molarity of Ba(OH)2 after the reaction
Tasya [4]

Answer:

<u></u>

  • <u>0.456M</u>

Explanation:

<u>1. Balanced molecular equation</u>

     2HNO_3+Ba(OH)_2\rightarrow Ba(NO_3)_2+2H_2O

<u>2. Mole ratio</u>

     \dfrac{2molHNO_3}{1molBa(OH)_2}

<u>3. Moles of HNO₃</u>

  • Number of moles = Molarity × Volume in liters
  • n = 0.600M × 0.0100 liter = 0.00600 mol HNO₃

<u>4. Moles Ba(OH)₂</u>

  • n = 0.700M × 0.0310 liter = 0.0217 mol

<u>5. Limiting reactant</u>

Actual ratio:

   \dfrac{0.0600molHNO_3}{0.0217molBa(OH)_2}\approx0.28

Since the ratio of the moles of HNO₃ available to the moles of Ba(OH)₂ available is less than the theoretical mole ratio, HNO₃ is the limiting reactant.

Thus, 0.006 moles of HNO₃ will react completely with 0.003 moles of Ba(OH)₂ and 0.0217 - 0.003 = 0.0187 moles will be left over.

<u>6. Final molarity of Ba(OH)₂</u>

  • Molarity = number of moles / volume in liters
  • Molarity = 0.0187 mol / (0.0100 + 0.0031) liter = 0.456M
5 0
3 years ago
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