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lakkis [162]
3 years ago
7

keeping in mind the role the order of precedence plays in equations, what would excel display as the result of the following equ

ation? =(24+75)/(6*3)
Mathematics
1 answer:
Alex73 [517]3 years ago
8 0
The answer to youre question is 5.5
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This is the power to which A number is raised or the number of times it is multiplied by itself
Anton [14]

Answer:

exponent

Step-by-step explanation:

7 0
3 years ago
How do I set up the problem?
vaieri [72.5K]
4x5=20
4x3=12
5x3=15

20+
12
15
------
47x2=94
6 0
3 years ago
Scott's company makes solid balls out of scrap metal for various industrial uses. For one project, he must make copper balls tha
Phantasy [73]
Explanation is in a file
5 0
3 years ago
-(-10x-8)=-(4x+10)<br> A)-4<br> B)-2<br> C)-3<br> D)3<br> show work
Eva8 [605]

Answer:

<h3>             None of given </h3><h3>                  x = -1²/₇ </h3>

Step-by-step explanation:

-(-10x - 8) = -(4x + 10)

  10x + 8 = -4x - 10

      -8            -8

     10x  =  -4x - 18

      +4x     +4x

     14x = -18

      ÷14    ÷14

      x = -¹⁸/₁₄ = -⁹/₇ = -1²/₇

I think you meant -(10x-8)=-(4x+10)

Then:

-(10x - 8) = -(4x + 10)

  -10x + 8 = -4x - 10

      -8            -8

     -10x  =  -4x - 18

       +4x     +4x

     -6x  =  -18

      ÷(-6)    ÷(-6)

<h3>         x = 3     D)</h3>
4 0
3 years ago
Prof Liu gave the same quiz to the students in her morning class and in her afternoon class. the average score for the two class
yaroslaw [1]

Answer:

Step-by-step explanation:

Given that Prof  Liu gave the same quiz to the students in her morning class and in her afternoon class. the average score for the two classes combined was 84.

(1) The average score for the students in the morning class was 80

(2) the average score for the students in the afternoon class was 86

Let m be the no of students in I class and n in II class

Total of I class = 80m and

Total of II class = 86n

Total of both classes = 80m +86n

Average =\frac{80m+86n}{m+n} = 84

m cannot be equal to n because in that case average would have been 83

If m >n, then say n =m+a

then average = \frac{80m+86m+86a}{2m+a} =84

Because 86 is more times added, average score would decrease hence we would not get 84.

So I class is getting less score of 80 to get a score average of more than 83 (the average) the class II should have more students.

4 0
3 years ago
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