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cluponka [151]
3 years ago
12

A car tire rotates with an average angular speed of 32 rad/s. In what time interval will the tire rotate 3.5 times? Answer in un

its of s.
Physics
1 answer:
stiks02 [169]3 years ago
3 0

Answer:

\Delta t = 0.687\ s

Explanation:

given,

Angular speed of the tire = 32 rad/s

Displacement of the wheel = 3.5 rev

Δ θ = 3.5 x 2 π

        = 7 π rad

now,

Time interval of the car to rotate 7π rad

using equation

\omega_{avg} =\dfrac{\Delta \theta}{\Delta t}

\Delta t=\dfrac{7\pi}{32}

\Delta t = 0.687\ s

Time taken to rotate 3.5 times is equal to 0.687 s.

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4 0
3 years ago
A spring with spring constant 13.1 N/m hangs from the ceiling. A ball is suspended from the spring and allowed to come to rest.
Alenkinab [10]

Answer:

Explanation:

spring constant, K = 13.1 N/m

22 oscillations in 20 seconds

time taken to complete one oscillation is called time period.

T = 20 / 22 second = 0.909 seconds

(a) let m be the mass.

The formula for the time period is

T = 2\pi \sqrt{\frac{m}{K}}

m = \frac{T^{2}K}{4\pi ^{2}}

m = \frac{0.909^{2}\times 13.1}{4\pi ^{2}}

m = 0.275 kg

(b) maximum speed, v = ω A = 2π A / T

v = ( 2 x 31.4 x 0.1) / 0.909

v = 0.691 m/s

6 0
3 years ago
A car starts from rest and accelerates uniformly over a time of 7.25 seconds for a distance of 210 m. Determine the acceleration
lara31 [8.8K]

Answer:

Acceleration is 7.990487515m/s²

Initial velocity is 0m.s

Explanation:

s=ut+(1/2)at²

210=0(7.25)+(1/2)a(7.25²)

210=26.28125a

∴a=7.990487515m/s²

'Vi' or 'u' is the inital speed. Since it starts from rest, this equals 0.

8 0
2 years ago
F(x)= 10x-5<br>What is the value of f-1(-4) ?​
Afina-wow [57]

Answer:

f^{-1}(-4) = \frac{1}{10}

Explanation:

Firstly finding f^{-1}(x)

So,

f(x) = 10x-5

Substitute y = f(x)

y = 10x-5

Exchange the values of x and y

x = 10y-5

Solving for y

x = 10y-5

Adding 5 to both sides

10y = x+5

Dividing both sides by 10

y = \frac{x+5}{10}

Replace y = f^{-1}(x)

f^{-1}(x) = \frac{x+5}{10}

For x = -4

f^{-1}(-4) = \frac{-4+5}{10}

f^{-1}(-4) = \frac{1}{10}

6 0
2 years ago
Read 2 more answers
A physicist drives through a stop light. When he is pulled over, he tells the police officer that the Doppler shift made the red
Orlov [11]

The physicist traveling, according to his own testimony at -6.6 × 10⁷ m/s.

<h3>How fast was the physicist traveling, according to his own testimony?</h3>

Using the formula for doppler shift for light,

λ' = λ√[(1 + v/c)/(1 - v/c)] where

  • λ = wavelength of source,
  • λ' = wavelength of observer,
  • v = speed of source and
  • c = speed of light

Given that the driver is moving away from the stop light, we take the driver as the source. Since, the Doppler shift made the red light of wavelength 650nm appear green to him, with a wavelength of 520nm. we have

  • λ' = wavelength of source = 650 nm,
  • λ' = wavelength of observer = 520 nm

So, substituting the values of the variables into the equation, we have

λ' = λ√[(1 + v/c)/(1 - v/c)]

520 nm = 650 nm√[(1 + v/c)/(1 - v/c)]

520/650 = √[(1 + v/c)/(1 - v/c)]

0.8 = √[(1 + v/c)/(1 - v/c)]

Squaring both sides, we have

0.8² = (1 + v/c)/(1 - v/c)

0.64 = (1 + v/c)/(1 - v/c)

0.64(1 - v/c) = (1 + v/c)

0.64 - 0.64v/c = 1 + v/c

0.64 - 1 = v/c + 0.64v/c

-0.36 = 1.64v/c

-0.2195 = v/c

v = -0.22c

v = -0.22 × 3 × 10⁸ m/s

v = -0.66 × 10⁸ m/s

v = -6.6 × 10⁷ m/s

So, the physicist traveling, according to his own testimony at -6.6 × 10⁷ m/s.

Learn more about doppler shift for light here:

brainly.com/question/28499579

#SPJ1

5 0
1 year ago
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