Explanation:
Let us assume that the given cylinder is 2.6 cm wide and its height is 3.1 cm. And, when piston is pushed down then the steady force is equal to 15 N.
Now, radius of the cylinder will be as follows.
r = 
= 
= 1.3 cm
or, = 0.013 m (as 1 m = 100 cm)
As, area of cylinder = 
= 
= 
Relation between pressure and force is as follows.
Pressure = 
= 
= 25996 
Since, 1 = 1 Pa (as 1 kPa = 1000 Pa)
Therefore, P = 25996
= 25.99 kPa
= 26 kPa (approx)
Thus, we can conclude that pressure of the gas inside the cylinder is 26 kPa.
Answer:
The best angular magnification is
-375
Explanation:
Fe = Fo - L
From the question, (Fo) = 1.08 cm while (L) = 0.56cm
Thus, Fe = 1.08 - 0.56 = 0.52cm
Now, let's apply the angular magnification equation ;
M = - Di/Do
Where Di is the distance from the lens to the image and Do is the distance of the object to the lens.
In this question, Di is represented by f which is the distance from the lens to the image and it is f= 195cm
Also,Do is represented by Fe which is 0.52cm and it is the distance of the object to the lens.
Thus m = - f/fe = - 195/0.52 = - 375
Answer:
Explanation:
Given
Velocity = 388m/s
Height S = 2.89m
Required
Time
Using the equation of motion
S =ut+1/2gt²
2.89 = 388t+1/2(9.8)t²
2.89 = 388t+4.9t²
Rearrange
4.9t²+388t-2.89 =0
Factorize
t = -388±√388²-4(4.9)(2.89)/2(4.9)
t= -388±√(388²-56.644)/9.8
t = -388±387.93/9.8
t =0.073/9.8
t = 0.00744 seconds
