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Free_Kalibri [48]
3 years ago
7

A small ball is attached to one end of a massless, rigid rod. The ball and the rod revolve in a horizontal circle with the other

end of the rod at the center. The path of the ball has a constant linear speed. The force exerted by the rod is 0.5 N. The mass of the ball is 3kg. What is the centripetal acceleration of the ball, in m/s2?
Physics
1 answer:
nikklg [1K]3 years ago
6 0

Explanation:

<em>i </em><em>don't </em><em>have </em><em>keyboard </em><em>of </em><em>mathametics </em><em>so </em><em>i </em><em>solve </em><em>this</em>

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Answer:

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Explanation:

Since the speed is constant, this means that the force applied to lift the equipment is equal to the weight of the equipment. So we can write:

F=mg

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m = 1000 kg is the mass

g=9.8 m/s^2 is the acceleration due to gravity

So,

F=(1000)(9.8)=9800 N

Then the work done in lifting the equipment is:

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Substituting,

W=(9800)(200)=1.96\cdot 10^6  J

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