Answer:
7.00 m
Explanation:
Given:
v₀ = 2.00 m/s
v = 5.00 m/s
a = 1.50 m/s²
Find: Δx
v² = v₀² + 2aΔx
(5.00 m/s)² = (2.00 m/s)² + 2(1.50 m/s²)Δx
Δx = 7.00 m
Answer:
7.5 m
Explanation:
= initial speed of the ball = 8 m/s
= angle of launch = 40° deg
Consider the motion along the vertical direction :
= initial velocity along vertical direction = 
= 8 Sin40 = 5.14 m/s
= acceleration along vertical direction = - 9.8 m/s²
= time of travel
= vertical displacement = - 1 m
Using the kinematics equation
= 1.22 sec
Consider the motion along the horizontal direction :
= initial velocity along horizontal direction = = 8 Cos40 = 6.13 m/s
= acceleration along vertical direction = 0 m/s²
= time of travel = 1.22 sec
= horizontal displacement = ?
Using the kinematics equation
= 7.5 m
Weight because both gravity and weight are pulling an object down
No, it couldn't be.
On that scale, Neptune would be almost 1,740 MILES from the sun.
ON THAT SCALE !
