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worty [1.4K]
3 years ago
12

PLZ HELP ME i don’t get this

Physics
1 answer:
Scorpion4ik [409]3 years ago
4 0

Explanation:

(i) Height of tree, h = 4 m

Mass of Ninja, m = 30 kg

The gravitational potential energy on the top branch of the tree is given by :

P=mgh

g is acceleration due to gravity

P=30\ kg\times 9.8\ m/s^2\times 4\ m\\\\P=1176\ J

(ii) If he were at a height of 2 meters from the ground, its potential energy will be :

P=mgh

g is acceleration due to gravity

P=30\ kg\times 9.8\ m/s^2\times 2\ m\\\\P=588\ J

Therefore, this is the required explanation.

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A silver sphere with radius 1.3611 cm at 23.0°C must slip through a brass ring that has an internal radius of 1.3590 cm at the s
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Answer:

The temperature must the ring be heated so that the sphere can just slip through is 106.165 °C.

Explanation:

For brass:

Radius = 1.3590 cm

Initial temperature = 23.0 °C

The sphere of radius 1.3611 cm must have to slip through the brass. Thus, on heating the brass must have to attain radius of 1.3611 cm

So,

Δ r = 1.3611 cm - 1.3590 cm = 0.0021 cm

<u>The linear thermal expansion coefficient of a metal is the ratio of the change in the length per 1 degree temperature to its length.</u>

<u>Thermal expansion for brass = 19×10⁻⁶ °C⁻¹</u>

Thus,

\alpha=\frac {\Delta r}{r\times \Delta T}

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So,

19\times 10^{-6}=\frac {0.0021}{1.3290\times (T_{final}-23.0)}

Solving for final temperature as:

(T_{final}-23.0)=\frac {0.0021}{1.3290\times 9\times 10^{-6}}

<u>Final temperature = 106.165 °C</u>

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