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enot [183]
3 years ago
10

When a 12 newton horizontal force is applied to a box on a horizontal

Physics
1 answer:
sdas [7]3 years ago
6 0

Answer:

ur mum

Explanation:

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A flying saucer lifts the Physical Science building 10,000 ft into the air before discovering it is useless and discards the rem
scZoUnD [109]

Answer:

500000000 lbft/s

Explanation:

F = Force or weight = 1000000 lbf

s = Displacement = 10000 ft

t = Time taken = 20 seconds

Work done is given by

W=Fs\\\Rightarrow W=1000000\times 10000\\\Rightarrow W=10000000000\ lb-ft

Power is given by

P=\dfrac{W}{t}\\\Rightarrow P=\dfrac{10000000000}{20}\\\Rightarrow P=500000000\ lbft/s

One Saucer power is 500000000 lbft/s

7 0
3 years ago
Someone please help its a simple power problem.
SOVA2 [1]
Well 200 doubled or (x2)=400 if that’s what it means
7 0
2 years ago
For adults age 19–50, Dietary Guidelines recommend consuming at least _______ of vegetables and fruits daily. A. 3 cups B. 1 to
Sauron [17]
<span>For adults age 19–50, Dietary Guidelines recommend consuming at least 4 cups of vegetables and fruits daily. this means the answer is C</span>
4 0
3 years ago
Read 2 more answers
15. Calculate The coefficient of kinetic friction be-
allochka39001 [22]

Answer:

Wt = 26.84 [N]

Explanation:

In order to solve this problem we must use the definition of work in physics. Which tells us that this is equal to the product of force by distance.

In this case, we must sum the works of the force applied by the box and the friction force that also acts on the box.

The friction force is defined as the product of the normal force by the coefficient of friction.

f = N*μ

where:

N = normal force = m*g [N] (units of Newtons)

m = mass = 72 [kg]

g = gravity acceleration = 9.81 [m/s²]

f = friction force [N]

μ = friction coefficient = 0.21

f = 72*9.81*0.21

f = 148.32 [N]

Now the total work:

Wt = WF - Wf

where:

Wt = total work [J] (units of Joules)

WF = work by the pushing force [J]

Wf = work done by the friction force [J]

Wt = (160*2.3) - (148.32*2.3)

Wt = 26.84 [N]

Note: The friction force exerts a negative work, because this force is acting in opposite direction to the movement, therefore the negative sign.

3 0
3 years ago
It is found experimentally that the electric field in a certain region of Earth's atmosphere is directed vertically down. At an
Lemur [1.5K]

Answer:

q=1.7346×10⁻⁶C

Explanation:

Since the electric field is perpendicular to the bottom and top of the cube,the total flux is equals the flux over the top of surface plus the flex over the lower surface

Ф(total)=Ф₃₀₀+Ф₂₃₀

But the flux is given by  Ф=E.A=EACos(θ) where θ is the angle between Area vector and electric field

So

Ф(total)=E₃₀₀A Cos(180)+E₂₃₀ACos(0)

Ф(total)=A(E₃₀₀ - E₂₃₀)

The total flux is given by Gauss Law as:

Ф(total)=q/ε₀

q=ε₀Ф(total)

q=ε₀(A(E₃₀₀ - E₂₃₀))

Substitute the given values

q=(8.85×10⁻¹²){(70²)(100 - 60)}

q=1.7346×10⁻⁶C

7 0
3 years ago
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