When a 12 newton horizontal force is applied to a box on a horizontal

xenn [34]

Answer:

It may seem as though burning destroys matter, but the same amount, or mass, of matter still exists after a campfire as before. Look at Figure 3.7.1 below. It shows that when wood burns, it combines with oxygen and changes not only to ashes, but also to carbon dioxide and water vapor. The gases float off into the air, leaving behind just the ashes. Suppose you had measured the mass of the wood before it burned and the mass of the ashes after it burned. Also suppose you had been able to measure the oxygen used by the fire and the gases produced by the fire. What would you find? The total mass of matter after the fire would be the same as the total mass of matter before the fire.

5 0

3 years ago

Parallel Plates Consider a very large conducting plate at potential V0 suspended a distance d above a very large grounded plane.

velikii [3]

Answer:

$V = \frac{V_0x}{d}$

Explanation:

Since the field lines are parallel and the electric field is uniform between two parallel plates, a test charge would experience the same force of attraction or repulsion no matter where it is located in the field,

I attached an image that could help to understand the representation of the field. The formula used to calculate it is given by,

$E= -\frac{\Delta V}{x}$ (1)

If we want to consider the change in Voltage with respect to the position then it would be,

$E= -\frac{dV}{dx}$

According to the information provided, the potential is $V_0$ and there is a distance d, therefore

$E= -\frac{V_0}{d}$ (2)

Taking equation (1) we can clear V, to what we have,

$\frac{dV}{dx} = -E$

$dV = -Edx$

Integrating,

$V= - \int Edx$

Substituting (2)

$V = -\int \frac{V_0}{d} dx$

$V = \frac{V_0x}{d}$

Where x is the height from the grounded plate.

8 0

4 years ago

What happens in a neutralization reaction?

damaskus [11]

<span>A neutralization reaction occurs when an acid and a base (usually both are in acqueous solutions) react to form water and a salt, which do not exhibit any of the acid or base properties. An acid is identified by being paired with a hydrogen ion and a base is identified by being paired with a hydroxide group.</span><span />

7 0

3 years ago

Read 2 more answers

The purpose of this piece of equipment is to

frozen [14]

A. Because that is a digital balance

6 0

4 years ago

A dog sees a flowerpot sail up and then back past a window 5.0 ft high. If the total time the pot is in sight is 1.0 seconds, fi

Kisachek [45]

To solve this problem we will use the linear motion kinematic equations for which acceleration (in this case gravity) is described as the change in velocity in an instant of time. Subsequently through the energy conservation equations we will find the net height.

Let's start considering that the time is 1 second, therefore,

$t = 1s$

Now the acceleration would be given as

$g = \frac{\Delta v}{t}$

$g = \frac{v_f-v_i}{t}$

$v_f-v_i = gt$

Since the final speed is zero, and the time elapsed to reach the height is 0.5 seconds (half of the entire route) we will have that the initial speed can be expressed in terms of gravity as

$0-v_i = g(\frac{1}{2})$