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kumpel [21]
3 years ago
7

Sally has read one-third of her book. She finishes the book by reading the same amount each night for 5 nights. Part A. What fra

ction of the book does she read each of the 5 nights
Mathematics
1 answer:
boyakko [2]3 years ago
6 0

Answer:

2/15

Step-by-step explanation:

Given that she have already read one-third of the book.

The fraction f of the book that will remain is;

f = 1 - 1/3 = 2/3

Then she finishes the book by reading the same amount each night for 5 nights

That implies she reads the remaining 2/3 of the book at equal rates for 5 nights.

Let x represent the fraction rate read per night;

5x = 2/3

Divide both sides by 5

x = 2/3 × 1/5

x = 2/15

Therefore, she reads 2/15 of the book every night for 5 nights.

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tankabanditka [31]

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16/13

Step-by-step explanation:

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7 0
3 years ago
The solution to 3x2 – 12x 24 = 0 is
zzz [600]
3x^2 - 12x + 24 = 0 \\ x^2 - 4x + 8 = 0 \\ x= \frac{-b \pm  \sqrt{ b^{2} -4ac} }{2a} &#10;; where a = 1, b = -4 and c = 8
x= \frac{-(-4) \pm \sqrt{ (-4)^{2} -4 \times 1 \times 8} }{2 \times 1} \\ = \frac{4 \pm \sqrt{ 16 -32} }{2} \\ =\frac{4 \pm \sqrt{ -16} }{2} \\ =\frac{4 \pm 4i }{2} \\ =2+2i \ or \ 2-2i
7 0
3 years ago
Read 2 more answers
When a deposit of $1000 is made into an account paying 2% interest, compounded annually, the balance, $B, in the account after t
labwork [276]

Answer:

The average rate of change in the balance over the interval t = 0 to t = 5 is of $20.82 a year. This means that the balance increased by $20.82 a year over the interval t = 0 to t = 5.

Step-by-step explanation:

Given a function y, the average rate of change S of y=f(x) in an interval (x_{s}, x_{f}) will be given by the following equation:

S = \frac{f(x_{f}) - f(x_{s})}{x_{f} - x_{s}}

In this problem, we have that:

B(t) = 1000(1.02)^{t}

Find the average rate of change in the balance over the interval t = 0 to t = 5.

B(0) = 1000(1.02)^{0} = 1000

B(5) = 1000(1.02)^{5} = 1104.08

Then

S = \frac{1104.08 - 1000}{5-0} = 20.82

The average rate of change in the balance over the interval t = 0 to t = 5 is of $20.82 a year. This means that the balance increased by $20.82 a year over the interval t = 0 to t = 5.

8 0
3 years ago
18. Determine the common difference, the fifth term, and the sum of the first 100 terms of the following sequence:
Ksenya-84 [330]

a_1=1,\ a_2=2.5,\ a_3=4,\ a_4=5.5,\ ...\\\\a_2-a_1=2.5-1=1.5\\a_3-a_2=4-2.5=1.5\\a_4-a_3=5.5-4=1.5\\a_{n+1}-a_n=1.5=constans\\\\\text{It's an arithmetic sequence with}\\a_1=1,\ \boxed{d=1.5}\\\\a_n=a_1+(n-1)d\to a_n=1+(n-1)(1.5)=1+1.5n-1.5\\\\a_n=1.5n-0.5\\\\a_5=1.5(5)-0.5=7.5-0.5=7\\\boxed{a_5=7}\\\\\text{The formula of a Sum of the First n Terms of an Arithmetric Sequence:}\\\\S_n=\dfrac{2a_1+(n-1)d}{2}\cdot n\\\\\text{We have:}\\a_1=1,\ d=1.5,\ n=100\\\\\text{Substitute}

S_{100}=\dfrac{(2)(1)+(100-1)(1.5)}{2}\cdot100=\dfrac{2+(99)(1.5)}{1}\cdot50\\\\=(2+148.5)\cdot50=150.5\cdot50=7,525\\\\\boxed{S_{100}=7,525}\\\\Answer:\\the\ common\ difference:\ d=1.5\\the\ fifth\ term:\ a_5=7\\the\ sum\ of\ first\ 100\ terms:\ S_{100}=7,525

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3 years ago
Using transformations
Delvig [45]
I have the graphed answer right here

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