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alekssr [168]
3 years ago
7

Evaluate each expression for s=4 and t=8 1) (25)^2t 2) 2st^2-5^2 3) 2s^2-t^3/16

Mathematics
1 answer:
stepladder [879]3 years ago
5 0

Answer:

<u>1.</u> 2.328×10^{22}

<u>2.</u> 487

<u>3.</u> 30.52  OR  0 (see explanation↓)

Step-by-step explanation:

<u>1.</u>(25)^{2t}

(sub for t=8)

=25^{2*8}

=25^{16}

=2.328×10^{22}

<u>2.</u>2st^{2} -5^{2}

(sub for s=4 and t=8)

=2×4×8^{2}-5^{2}

=512-25

=487

<u>3.</u>2s^{2} -t^{3/16} (the equation is not clear so I will do 2s^{2} -\frac{t^{3} }{16} as well)

<u>FOR</u> 2s^{2} -t^{3/16}

(sub s=4 and t=8)

=2×4^{2}-8^{3/16}

=32-1.476826146

=30.52 (to the nearest 2 decimal place)

<u>FOR</u> 2s^{2} -\frac{t^{3} }{16}

(sub s=4 and t=8)

=2×4^{2}-\frac{8^{3} }{16}

=32-32

=0

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Answer:

<h2>A)t=6.7</h2>

Step-by-step explanation:

<h3>to understand this</h3><h3>you need to know about:</h3>
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<h3>given:</h3>

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<h3>to solve:</h3>

t

<h3>tips and formulas:</h3>
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<h3>let's solve: </h3>

step - 1 :  \: define

- 4 {t}^{2}  + 12t + 100 = 0

step - 2 :  \\ divide \: both \: sides \: by \:  - 4

{t}^{2}  - 3t - 25 = 0

step - 3 :  \\ solve \: the \: quadratic

formula :  \\ x =  \frac{ - b± \sqrt{ {b}^{2} - 4ac }  }{2a}

define \: a ,b \: and \: c \\ which \: are \: 1, - 3 \: and \:  - 25 \: respectively

t =  \frac{ - ( - 3)± \sqrt{ {( - 3)}^{2} - 4.1. - 25 }  }{2.1}

t =  \frac{  3± \sqrt{ 9    + 100}  }{2}

t = \frac{3 +  \sqrt{ 109 } }{2}

t =  \frac{3  -  \sqrt{ 109 } }{2}

t = 6.7 \\ t =  - 3.7

as \: we \: know \: time \: cannot \: be \: negative

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Answer:

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