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alekssr [168]
3 years ago
7

Evaluate each expression for s=4 and t=8 1) (25)^2t 2) 2st^2-5^2 3) 2s^2-t^3/16

Mathematics
1 answer:
stepladder [879]3 years ago
5 0

Answer:

<u>1.</u> 2.328×10^{22}

<u>2.</u> 487

<u>3.</u> 30.52  OR  0 (see explanation↓)

Step-by-step explanation:

<u>1.</u>(25)^{2t}

(sub for t=8)

=25^{2*8}

=25^{16}

=2.328×10^{22}

<u>2.</u>2st^{2} -5^{2}

(sub for s=4 and t=8)

=2×4×8^{2}-5^{2}

=512-25

=487

<u>3.</u>2s^{2} -t^{3/16} (the equation is not clear so I will do 2s^{2} -\frac{t^{3} }{16} as well)

<u>FOR</u> 2s^{2} -t^{3/16}

(sub s=4 and t=8)

=2×4^{2}-8^{3/16}

=32-1.476826146

=30.52 (to the nearest 2 decimal place)

<u>FOR</u> 2s^{2} -\frac{t^{3} }{16}

(sub s=4 and t=8)

=2×4^{2}-\frac{8^{3} }{16}

=32-32

=0

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Answer:

Follows are the solution to the given points:

Step-by-step explanation:

Given:

A) \ \ 2x+(3.4)^2+(7.7) \\\\B) \ \ 3x+(2.6)+(8.8)^2\\\\C)\ \ 7.6+(28.3)+(4)^2 \\\\D)\ \ 7x-(7.8)+(9:3)

For point A:

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For point B:

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For point C:

\to \ 7.6+(28.3)+(4)^2 \\\\\to \ 7.6+(28.3)+16 \\\\\to \ 7.6+44.3 \\\\\to 51.9

For point D:

\to 7x-(7.8)+(9:3)\\\\\to 7x-(7.8)+ \frac{9}{3}\\\\\to 7x- \frac{23.4+9}{3}\\\\\to 7x- \frac{32.4}{3}\\\\\to 7x- 10.8

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