Here we want to present growth as a function of time; the growth depends upon the number of days that go by. So, growth(y) is the dependent variable and time (in days, x) is the independent variable.

7 0

3 years ago

Jennifer taking a quiz and has answered 13 questions so far. If there are 25 questions on Jennifer test, how many questions does

Stels [109]

Answer: 12

Step-by-step explanation: To figure this out you have to subtract 25 by 13

- 13

= 12

7 0

3 years ago

Which table shows a function that is decreasing over the interval (-2, 0)?

saveliy_v [14]

Answer:

it is becoming a actual number and not a negative

4 0

2 years ago

A prior study estimated as 34%. The analysts would like to conduct a second study on the same topic with a margin of error, E, o

Volgvan

The minimum sample size required for a test with a confidence interval of $100(1 - \alpha )%$ with a z-score of $z_{ \alpha /2}$ and margin of error of E and a population proportion of p is given by:

$n= \frac{p(1-p)z_{ \alpha /2}^2 \alpha }{E^2}$

Given p = 34% = 0.34, E = 0.027, $z_{ \alpha /2}=1.645$

Therefore,

$n= \frac{0.34(1-0.34)(1.645)^2}{0.027^2} \\ \\ = \frac{0.34(0.66)(2.706025)}{0.000729} = \frac{0.60723201}{0.000729} \\ \\ =832.97=833$

4 0

2 years ago

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