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3 years ago

Divide. Write in simplest form. To type a mixed number, leave a space between the whole number and the fraction.

Mathematics

1 answer:

Iteru [2.4K]3 years ago

8 0

1. 1/4
2. 3/36= 1/12
3. 1/24

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A 41 gram sample of a substance that's used to detect explosives has a k-value of 0.1392. Find the substance's half life, in day

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Answer:

The substance half-life is of 4.98 days.

Step-by-step explanation:

Equation for an amount of a decaying substance:

The equation for the amount of a substance that decay exponentially has the following format:

$A(t) = A(0)e^{-kt}$

In which k is the decay rate, as a decimal.

k-value of 0.1392.

This means that:

$A(t) = A(0)e^{-0.1392t}$

Find the substance's half life, in days.

This is t for which $A(t) = 0.5A(0)$ . So

$A(t) = A(0)e^{-0.1392t}$

$0.5A(0) = A(0)e^{-0.1392t}$

$e^{-0.1392t} = 0.5$

$\ln{e^{-0.1392t}} = \ln{0.5}$

$-0.1392t = \ln{0.5}$

$t = -\frac{\ln{0.5}}{0.1392}$

$t = 4.98$

The substance half-life is of 4.98 days.

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2 years ago

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3 years ago

What is the estimate of 6296

Papessa [141]

Ans:6300

Explanation: Estimating the value of 6296+0
Round up the number 6296 to 6300.
6300+0
Round up the number 0 to 0.
6300+0
Add 0 to 6300.
6300
6296+0≈6300
The Estimated Value of 6296+0 is 6300.

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