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Marianna [84]
3 years ago
9

in chess, Justin won 20 games, tied 8 games, and lost 14 games last year. What is Justin’s ratio of total games to tied games

Mathematics
2 answers:
zhuklara [117]3 years ago
7 0
Problem: In chess, Justin won 20 games, tied 8 games, and lost 14 games last year. What is Justin’s ratio of total games to tied gamesSolutions:=> There are a total of 20 games=> 8 of them were tied=> 14 games were lost.Now, let's find the ratio of the tied games to the total games.=> Since the total game is 20 and the tied games are 8, therefore the ratio will be:<span>=> 8 : 20, where 8 are the tied games and 20 is the total</span>
antiseptic1488 [7]3 years ago
4 0

Answer:

He would win around 79%

Step-by-step explanation:

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Scrat [10]

Answer:

15 sq. cm.

Step-by-step explanation:

Each of the full squares are 1 so each of the half squares are .5

There are 12 full squares and 6 half squares. If you add those half squares you will get 15 sq. cm.

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Alex bought a new aquarium. He is in the process of setting it up. The aquarium is in the shape
KengaRu [80]

Answer:

39.00%

Step-by-step explanation:

Given

Dimension: 36⅞ by 19 by 24⅝

Volume of Water = 6039in³

Required

What percent of the volume of the aquarium is filled with water?

First, we need to calculate the volume of the aquarium.

This is calculated by multiplying the dimensions of the aquarium

Volume = 36⅞ * 19 * 24⅝

Volume = 295/8 * 19 * 197/8

Volume = 1104185/64

Volume = 17252.89

The percent filled with water is calculated using the following formula:

%Percent = (Volume of water * 100%)/(Volume of aquarium)

%Percent = (6039 * 100%)/(17252.89)

%Percent = (603900%)/(17252.89)

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Hence, the water occupies 39.00% of the aquarium

4 0
3 years ago
Evaluate 4 + 6 x 6 / 8
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Answer:

8.5

Step-by-step explanation:

4 + (6)(6)/8=

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2 years ago
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A pack of cinnamon-scented pencils sells for $5.00. What is the sales tax rate if the total cost of the pencils is $5.15?
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3 years ago
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A maintenance manager must test a new repair method that should increase the expected time between repairs. For each machine use
Murljashka [212]

Answer:

a) The value t=1.73 < 1.833 fall in the acceptance region, so the effect is not significant. The null hypothesis can not be rejected.

The claim that the new method is better doesn't have enough statistical evidence.

b) P-value=0.06

c) 95% CI

-25 \leq\mu_n-\mu_c\leq  189

Step-by-step explanation:

A) We have to test the hypothesis about the difference of the means.

The claim is that the new method gives larger times between repairs.

1) State the null and alternative hypothesis

H_0: \mu_n\leq\mu_c\\\\H_a: \mu_n>\mu_c

The significance level is 0.05.

2) The sample mean and standard deviation of the current method is

M_c=254\\\\ s_c=113

The sample mean and standard deviation of the new method is

M_n=336\\\\ s_n=99

The difference of means is

M_d=M_n-M_c=336-254=82

The standard deviation of the difference of means can be estimated as:

s_d=\sqrt{\frac{s_n^2+s_c^2}{n} }=\sqrt{\frac{99^2+113^2}{10} }=\sqrt{2246}=47.4

3) Then, we can calculate the t-statistic as:

t=\frac{M_d-(\mu_n- \mu_c)}{s_d} =\frac{82-0}{47.4}=1.73

4) For 9 degrees of freedom and a significance level of 0.05, the critical value for t is t=1.833.

5) The value t=1.73 < 1.833 fall in the acceptance region, so the effect is not significant. The null hypothesis can not be rejected.

The claim that the new method is better doesn't have enough statistical evidence.

B) For a df=10-1=9 and t=1.73, the P-value is

P(t_9>1.73)=0.06

C) In this case, for 9 degrees of freedom and 95% CI, the critical value of t is t=2.262.

The CI can be written as:

M_d-t*s_d\leq\mu_n-\mu_c\leqM_d+t*s_d\\\\82-2.262*47.4\leq\mu_n-\mu_c\leq 82+2.262*47.4\\\\82-107\leq\mu_n-\mu_c\leq 82+107\\\\-25 \leq\mu_n-\mu_c\leq  189

7 0
3 years ago
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